Christine Mann
James Murray
2021-01-18 #87927 Woodham Ferrers Bridge Club
Christine Mann
James Murray
Average 46.25
Ranking 5th
PDF converter   

 
Board Pair NS EW Pct MP Played
AS
Contract Shape
  1 Alan Brabant - Lionel Thacker 400   100   NS 5= by S Lead 2
     
  2   110   100   NS 3= by S Lead 3
     
  3     120 0   NS 2NT= by W Lead 4
     
  4     110 50   NS 2= by E Lead 5
     
  5 Graham Meldrum - Kay Rippon 140   0   EW 3= by S Lead T
     
  6   140   100   EW 3= by N Lead A
     
  7     620 50   EW 4= by E Lead 4
     
  8     50 50   EW 1-1 by N Lead A
     
  9 Naomi Wallace - Phil Rackley   50 0   EW 3-1 by S Lead A
     
  10   200   0   EW 2-2 by W Lead 8
     
  11     400 100   EW 3NT= by E Lead 4
     
  12   680   75   EW 4+2 by S Lead 7
     
  13 Linda Barker - Peter Bailey 110   0   EW 2= by N Lead A
     
  14     50 50   EW 3-1 by S Lead A
     
  15     450 75   EW 4+1 by E Lead Q
     
  16     690 50   EW 3NT+3 by E Lead A
     
  17 Irene Bessell - Trevor Elcock   140 0   NS 2+1 by E Lead 8
     
  18     480 50   NS 4+2 by E Lead J
     
  19     150 75   NS 3-3 by S Lead A
     
  20     120 0   NS 1NT+1 by E Lead K
     
Player Statistics
North
Declarer  
Dummy392%
1°Def10%
2°Def425%
East
Declarer469%
Dummy10%
1°Def350%
2°Def431%
South
Declarer392%
Dummy  
1°Def425%
2°Def10%
West
Declarer10%
Dummy469%
1°Def431%
2°Def350%

Average Points
North9.618.8
South9.2
East11.221.2
West10

Distribution
4.3.3.3.810%
4.4.3.2.1721.2%
4.4.4.1.11.2%
5.3.3.2.1215%
5.4.2.2.1113.8%
5.4.3.1.1316.2%
5.4.4.0.11.2%
5.5.2.1.22.5%
5.5.3.0.11.2%
6.3.2.2.45%
6.3.3.1.11.2%
6.4.2.1.22.5%
6.4.3.0.45%
6.5.1.1.22.5%
8.2.2.1.11.2%

N
S
Board 1
400
100%

QJ3
KQ953
109632
8
6 10
16
Alan Brabant
Lionel Thacker
  
J7542
962
AJ84
7
AQ1086
A107
762
84
5= by S Lead 2
par:400.5 (N)
 NT
N11  9  9  6  7
S11  9  9  6  7
E  2  3  3  7  4
W  2  3  3  7  4
Double Dummy Solv:Bo Haglund
 
K93
K854
10
AKQJ5
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Christine Mann - James Murray 2 Alan Brabant - Lionel Thacker 400   100 0 5= by S Lead 2
6 Graham Meldrum - Kay Rippon 4 Naomi Wallace - Phil Rackley 150   50 50 4+1 by S Lead 6
1 Linda Barker - Peter Bailey 3 Irene Bessell - Trevor Elcock   50 0 100 2-1 by S Lead 7
N
S
Board 2
110
100%
K82
K1095
K754
76
9
10 11
10
Alan Brabant
Lionel Thacker
  
AQJ
873
J1098
Q42
1094
AQJ642
32
A5
3= by S Lead 3
par:100.3X-1 (E)
 NT
N  9  7  5  8  6
S  9  7  4  7  4
E  4  6  8  5  7
W  4  6  8  5  7
Double Dummy Solv:Bo Haglund
 
7653

AQ6
KJ10983
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Christine Mann - James Murray 2 Alan Brabant - Lionel Thacker 110   100 0 3= by S Lead 3
1 Linda Barker - Peter Bailey 3 Irene Bessell - Trevor Elcock 50   50 50 3-1 by E Lead 7
6 Graham Meldrum - Kay Rippon 4 Naomi Wallace - Phil Rackley   200 0 100 3-2 by N Lead A

N
S
Board 3
-120
0%
1096
KQ643
Q852
9
7
6 17
10
Alan Brabant
Lionel Thacker
  
42
J108
AJ43
8652
KQ85
2
K97
AKQ43
2NT= by W Lead 4
par:-100.4X-1 (N)
 NT
N  2  5  9  7  5
S  2  5  9  7  5
E10  8  4  6  7
W10  8  4  6  7
Double Dummy Solv:Bo Haglund
 
AJ73
A975
106
J107
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 3 Irene Bessell - Trevor Elcock 140   100 0 3= by N Lead A
6 Graham Meldrum - Kay Rippon 4 Naomi Wallace - Phil Rackley   90 50 50 2= by E Lead T
5 Christine Mann - James Murray 2 Alan Brabant - Lionel Thacker   120 0 100 2NT= by W Lead 4
N
S
Board 4
-110
50%
KJ92
KJ4
J
J10873
10
9 11
10
Alan Brabant
Lionel Thacker
  
Q764
Q6
K10973
Q4
8
A107532
A2
K962
2= by E Lead 5
par:-140.3 (E)
 NT
N  7  6  4  8  6
S  7  6  3  8  6
E  6  7  9  5  7
W  6  7  9  5  7
Double Dummy Solv:Bo Haglund
 
A1053
98
Q8654
A5
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 3 Irene Bessell - Trevor Elcock 100   100 0 3-1 by E Lead A
5 Christine Mann - James Murray 2 Alan Brabant - Lionel Thacker   110 50 50 2= by E Lead 5
6 Graham Meldrum - Kay Rippon 4 Naomi Wallace - Phil Rackley   140 0 100 2+1 by E Lead 6

E
W
Board 5
140
0%
K106
97
J943
KQ43
9
8 9
14
Graham Meldrum
Kay Rippon
  
A7543
Q84
Q62
105
J82
65
K107
AJ987
3= by S Lead T
par:100.2X-1 (E)
 NT
N  6  8  8  6  7
S  6  8  8  6  7
E  7  5  5  7  5
W  7  5  5  7  5
Double Dummy Solv:Bo Haglund
 
Q9
AKJ1032
A85
62
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Graham Meldrum - Kay Rippon 5 Christine Mann - James Murray 140   100 0 3= by S Lead T
3 Irene Bessell - Trevor Elcock 2 Alan Brabant - Lionel Thacker 50   50 50 3-1 by W Lead 9
1 Linda Barker - Peter Bailey 4 Naomi Wallace - Phil Rackley   100 0 100 3-1 by S Lead T
E
W
Board 6
140
100%
AK82
KQ876

J742
13
9 11
7
Graham Meldrum
Kay Rippon
  
963
J43
J42
AK95
Q1054
52
AKQ109
108
3= by N Lead A
par:420.4 (N)
 NT
N  8  510  7  6
S  8  510  7  6
E  5  8  3  6  6
W  5  8  3  6  6
Double Dummy Solv:Bo Haglund
 
J7
A109
87653
Q63
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 4 Naomi Wallace - Phil Rackley 200   100 0 2NT-2 by W Lead K
3 Irene Bessell - Trevor Elcock 2 Alan Brabant - Lionel Thacker 170   50 50 2+2 by N Lead A
6 Graham Meldrum - Kay Rippon 5 Christine Mann - James Murray 140   0 100 3= by N Lead A

E
W
Board 7
-620
50%
8763
A4
J3
Q8654
7
11 14
8
Graham Meldrum
Kay Rippon
  
AJ9
K87
107652
K2
Q
QJ1053
KQ4
A1097
4= by E Lead 4
par:-660.3NT+2 (E)
 NT
N  4  2  2  6  2
S  4  2  2  6  2
E  91011  711
W  91011  711
Double Dummy Solv:Bo Haglund
 
K10542
962
A98
J3
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 4 Naomi Wallace - Phil Rackley   170 100 0 3+1 by E Lead J
6 Graham Meldrum - Kay Rippon 5 Christine Mann - James Murray   620 50 50 4= by E Lead 4
3 Irene Bessell - Trevor Elcock 2 Alan Brabant - Lionel Thacker   650 0 100 4+1 by E Lead J
E
W
Board 8
-50
50%
AK109
Q62
J107
KQ8
15
10 11
4
Graham Meldrum
Kay Rippon
  
QJ86
K3
A853
764
32
A1087
K62
A1053
1-1 by N Lead A
par:-80.1 (W)
 NT
N  6  6  7  6  6
S  6  6  7  6  6
E  7  7  6  6  6
W  7  7  6  7  6
Double Dummy Solv:Bo Haglund
 
754
J954
Q94
J92
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 4 Naomi Wallace - Phil Rackley 50   100 0 2-1 by W Lead K
6 Graham Meldrum - Kay Rippon 5 Christine Mann - James Murray   50 50 50 1-1 by N Lead A
3 Irene Bessell - Trevor Elcock 2 Alan Brabant - Lionel Thacker   100 0 100 3-2 by S Lead 6

E
W
Board 9
-50
0%
Q9
KJ732
9
J10875
7
13 13
7
Naomi Wallace
Phil Rackley
  

1086
A76532
AKQ9
A74
AQ9
QJ108
632
3-1 by S Lead A
par:-2220.7NT (E)
 NT
N  3  0  2  7  0
S  3  0  2  7  0
E101311  613
W101311  613
Double Dummy Solv:Bo Haglund
 
KJ1086532
54
K4
4
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Naomi Wallace - Phil Rackley 5 Christine Mann - James Murray   50 100 0 3-1 by S Lead A
3 Irene Bessell - Trevor Elcock 6 Graham Meldrum - Kay Rippon   1370 50 50 6= by W Lead Q
1 Linda Barker - Peter Bailey 2 Alan Brabant - Lionel Thacker   1390 0 100 6+1 by E Lead K
E
W
Board 10
200
0%
K1064
A82
K104
1054
10
12 7
11
Naomi Wallace
Phil Rackley
  
AQ9875
Q5
J85
QJ
2
K74
97632
A982
2-2 by W Lead 8
par:600.3NT (N)
 NT
N  8  5  8  7  9
S  8  5  8  7  9
E  5  7  4  6  4
W  5  7  4  6  4
Double Dummy Solv:Bo Haglund
 
J3
J10963
AQ
K763
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Naomi Wallace - Phil Rackley 5 Christine Mann - James Murray 200   100 0 2-2 by W Lead 8
3 Irene Bessell - Trevor Elcock 6 Graham Meldrum - Kay Rippon 170   50 50 3+1 by S Lead 8
1 Linda Barker - Peter Bailey 2 Alan Brabant - Lionel Thacker 140   0 100 3= by S Lead Q

E
W
Board 11
-400
100%
Q106
K106
QJ3
KQ107
13
14 12
1
Naomi Wallace
Phil Rackley
  
A543
QJ5
AK10954
KJ9
A972
86
A982
3NT= by E Lead 4
par:-1510.7 (E)
 NT
N  5  1  1  0  1
S  5  1  1  0  1
E  812121310
W  812121310
Double Dummy Solv:Bo Haglund
 
872
843
72
J6543
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Irene Bessell - Trevor Elcock 6 Graham Meldrum - Kay Rippon   150 100 0 3+2 by W Lead K
1 Linda Barker - Peter Bailey 2 Alan Brabant - Lionel Thacker   200 50 50 2+3 by W Lead K
4 Naomi Wallace - Phil Rackley 5 Christine Mann - James Murray   400 0 100 3NT= by E Lead 4
E
W
Board 12
680
75%
A3
AQ72
85
KQ953
15
7 3
15
Naomi Wallace
Phil Rackley
  
QJ974
J64
Q63
J4
8652
98
K109
10876
4+2 by S Lead 7
par:1430.6 (N)
 NT
N111112  711
S111112  711
E  2  2  1  5  2
W  2  2  1  5  2
Double Dummy Solv:Bo Haglund
 
K10
K1053
AJ742
A2
 
WNES
1 1
1N 2
3 4
1430(1) 100%680(2) 25%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 2 Alan Brabant - Lionel Thacker 1430   100 0 6= by N Lead 6
4 Naomi Wallace - Phil Rackley 5 Christine Mann - James Murray 680   25 75 4+2 by S Lead 7
3 Irene Bessell - Trevor Elcock 6 Graham Meldrum - Kay Rippon 680   25 75 4+2 by N Lead 8

E
W
Board 13
110
0%
KJ10765
9
K93
J52
8
10 12
10
Linda Barker
Peter Bailey
  
Q4
AQ1083
Q10874
3
983
J752
A6
AK108
2= by N Lead A
par:-620.4 (E)
 NT
N  7  3  2  7  5
S  7  3  2  7  5
E  6  910  5  7
W  6  910  5  7
Double Dummy Solv:Bo Haglund
 
A2
K64
J52
Q9764
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 5 Christine Mann - James Murray 110   100 0 2= by N Lead A
4 Naomi Wallace - Phil Rackley 3 Irene Bessell - Trevor Elcock 100   50 50 4-1 by W Lead 9
2 Alan Brabant - Lionel Thacker 6 Graham Meldrum - Kay Rippon   620 0 100 4= by W Lead 7
E
W
Board 14
-50
50%
K6
Q543
Q876
K82
10
9 7
14
Linda Barker
Peter Bailey
  
2
J10976
AK9543
J
QJ105
A82
2
109754
3-1 by S Lead A
par:100.3X-1 (E)
 NT
N  8  5  5  8  7
S  8  5  5  8  7
E  5  8  7  5  5
W  5  8  7  5  5
Double Dummy Solv:Bo Haglund
 
A98743
K
J10
AQ63
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Alan Brabant - Lionel Thacker 6 Graham Meldrum - Kay Rippon 110   100 0 2= by S Lead A
1 Linda Barker - Peter Bailey 5 Christine Mann - James Murray   50 50 50 3-1 by S Lead A
4 Naomi Wallace - Phil Rackley 3 Irene Bessell - Trevor Elcock   100 0 100 4-2 by S Lead A

E
W
Board 15
-450
75%
1032
J10985
K107
K3
7
8 16
9
Linda Barker
Peter Bailey
  
J8654
A
842
QJ84
AKQ97
K72
A965
7
4+1 by E Lead Q
par:-450.4+1 (E)
 NT
N  8  4  9  2  4
S  8  4  9  2  4
E  5  9  411  8
W  5  8  411  8
Double Dummy Solv:Bo Haglund
 

Q643
QJ3
A109652
 
WNES
   
1X
3 4
-420(1) 100%-450(2) 25%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Alan Brabant - Lionel Thacker 6 Graham Meldrum - Kay Rippon   420 100 0 4= by E Lead Q
4 Naomi Wallace - Phil Rackley 3 Irene Bessell - Trevor Elcock   450 25 75 4+1 by E Lead A
1 Linda Barker - Peter Bailey 5 Christine Mann - James Murray   450 25 75 4+1 by E Lead Q
E
W
Board 16
-690
50%
986
96
Q762
K874
5
12 17
6
Linda Barker
Peter Bailey
  
QJ103
KQJ83
K4
62
K74
A4
A1098
AQ109
3NT+3 by E Lead A
par:-1440.6NT (E)
 NT
N  2  2  1  1  1
S  2  2  1  1  1
E1111121212
W1011121212
Double Dummy Solv:Bo Haglund
 
A52
10752
J53
J53
 
WNES
1 2
2 3N
-690(2) 50%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Alan Brabant - Lionel Thacker 6 Graham Meldrum - Kay Rippon   690 50 50 3NT+3 by E Lead 3
1 Linda Barker - Peter Bailey 5 Christine Mann - James Murray   690 50 50 3NT+3 by E Lead A
4 Naomi Wallace - Phil Rackley 3 Irene Bessell - Trevor Elcock     50 50 ??

N
S
Board 17
-140
0%
J72
62
AKQ2
K832
13
13 7
7
Irene Bessell
Trevor Elcock
  
AKQ94
8743
84
A7
1063
KQ95
10975
Q10
2+1 by E Lead 8
par:100.3X-1 (E)
 NT
N  9  9  5  5  6
S  9  9  5  5  6
E  4  4  8  8  6
W  4  4  8  8  6
Double Dummy Solv:Bo Haglund
 
85
AJ10
J63
J9654
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 6 Graham Meldrum - Kay Rippon   50 100 0 1NT-1 by S Lead A
2 Alan Brabant - Lionel Thacker 4 Naomi Wallace - Phil Rackley   110 50 50 2= by W Lead A
5 Christine Mann - James Murray 3 Irene Bessell - Trevor Elcock   140 0 100 2+1 by E Lead 8
N
S
Board 18
-480
50%
K742
Q9
KQJ53
Q7
13
6 16
5
Irene Bessell
Trevor Elcock
  
Q1085
K8652
4
J109
A963
AJ743
2
AK2
4+2 by E Lead J
par:-980.6 (E)
 NT
N  4  9  1  1  1
S  4  9  1  1  1
E  9  41212  7
W  9  41212  7
Double Dummy Solv:Bo Haglund
 
J
10
A109876
86543
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Alan Brabant - Lionel Thacker 4 Naomi Wallace - Phil Rackley   450 100 0 4+1 by E Lead J
5 Christine Mann - James Murray 3 Irene Bessell - Trevor Elcock   480 50 50 4+2 by E Lead J
1 Linda Barker - Peter Bailey 6 Graham Meldrum - Kay Rippon   500 0 100 5X-2 by N Lead A

N
S
Board 19
-150
75%
7532
J98
J8
AQ103
8
11 15
6
Irene Bessell
Trevor Elcock
  
A
7532
AK103
8642
K6
AK64
Q9652
K7
3-3 by S Lead A
par:-650.4+1 (E)
 NT
N  4  2  2  6  2
S  4  2  2  6  2
E  81111  710
W  81111  710
Double Dummy Solv:Bo Haglund
 
QJ10984
Q10
74
J95
 
WNES
   2
3
-150(2) 75%-600(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Christine Mann - James Murray 3 Irene Bessell - Trevor Elcock   150 75 25 3-3 by S Lead A
1 Linda Barker - Peter Bailey 6 Graham Meldrum - Kay Rippon   150 75 25 3-3 by S Lead A
2 Alan Brabant - Lionel Thacker 4 Naomi Wallace - Phil Rackley   600 0 100 3NT= by E Lead Q
N
S
Board 20
-120
0%
A10653
976
4
Q1098
6
16 4
14
Irene Bessell
Trevor Elcock
  
42
AKJ8
A87
A654
987
104
96532
KJ3
1NT+1 by E Lead K
par:-120.1NT+1 (E)
 NT
N  5  4  5  7  5
S  5  4  5  7  5
E  8  8  8  6  8
W  8  8  8  6  8
Double Dummy Solv:Bo Haglund
 
KQJ
Q532
KQJ10
72
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Barker - Peter Bailey 6 Graham Meldrum - Kay Rippon 80   100 0 1= by N Lead 3
2 Alan Brabant - Lionel Thacker 4 Naomi Wallace - Phil Rackley   100 50 50 2-1 by N Lead T
5 Christine Mann - James Murray 3 Irene Bessell - Trevor Elcock   120 0 100 1NT+1 by E Lead K