Heather Carr
Mary Carter
2023-01-25 #68461 Lancashire Online LOP Open Pairs
Heather Carr
Mary Carter
Average 50
Ranking 3rd
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Board Pair NS EW Pct MP Played
AS
Contract Shape
  1 Linda Hitchen - Wynn Sutherland 100   100   NS 6NT-2 by E Lead 5
     
  2   110   100   NS 3= by S Lead J
     
  3   100   100   NS 5-1 by E Lead A
     
  4     200 0   NS 3-2 by S Lead A
     
  5     110 100   NS 2+1 by E Lead 2
     
  6     170 0   NS 1+3 by E Lead 2
     
  7 Dave Stamp - Ijsklont 150   50   NS 2NT+1 by N Lead 9
     
  8   460   100   NS 3NT+2 by N Lead 9
     
  9   100   100   NS 2-1 by E Lead 4
     
  10   110   0   NS 2= by N Lead K
     
  11     100 50   NS 1NT-2 by S Lead 9
     
  12   620   100   NS 4= by N Lead 2
     
  13 Arthur Southwood - Melba Southwood 120   0   NS 1NT+1 by N Lead 9
     
  14     420 0   NS 4= by W Lead 4
     
  15   650   0   NS 4+1 by S Lead A
     
  16   110   50   NS 2= by S Lead A
     
  17     430 0   NS 3NT+1 by E Lead 4
     
  18     480 50   NS 4+2 by E Lead 7
     
Player Statistics
North
Declarer550%
Dummy540%
1°Def10%
2°Def764%
South
Declarer540%
Dummy550%
1°Def764%
2°Def10%

Average Points
North9.119.5
South10.4
East11.620.5
West8.9

Distribution
4.3.3.3.1419.4%
4.4.3.2.1520.8%
4.4.4.1.22.8%
5.3.3.2.1115.3%
5.4.2.2.811.1%
5.4.3.1.56.9%
5.4.4.0.11.4%
5.5.2.1.22.8%
5.5.3.0.11.4%
6.3.2.2.45.6%
6.3.3.1.11.4%
6.4.2.1.22.8%
6.4.3.0.11.4%
6.5.2.0.11.4%
7.2.2.2.11.4%
7.3.2.1.22.8%
8.4.1.0.11.4%

N
S
Board 1
100
100%
J1094
A82
874
1052
5
11 20
4
Linda Hitchen
Wynn Sutherland
  
A8765
J9
Q106
A84
KQ
Q104
AK93
KQJ9
6NT-2 by E Lead 5
par:-460.3NT+2 (E)
 NT
N  1  1  3  2  2
S  1  1  3  2  2
E1111  91011
W1111  91011
Double Dummy Solv:Bo Haglund
 
32
K7653
J52
763
 
WNES
  2N*
3 3
4N 5
5N 6
6N
100(1) 100%50(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 4 Linda Hitchen - Wynn Sutherland 100   100 0 6NT-2 by E Lead 5
2 Arthur Southwood - Melba Southwood 1 Dave Stamp - Ijsklont 50   0 100 6NT-1 by E Lead 5
N
S
Board 2
110
100%

J10963
A10972
J106
6
8 12
14
Linda Hitchen
Wynn Sutherland
  
J987
Q84
Q43
K53
A106543
K52
K5
Q2
3= by S Lead J
par:100.3X-1 (E)
 NT
N  9  9  8  5  8
S  9  9  8  5  8
E  4  3  5  8  5
W  3  3  4  8  5
Double Dummy Solv:Bo Haglund
 
KQ2
A7
J86
A9874
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 4 Linda Hitchen - Wynn Sutherland 110   100 0 3= by S Lead J
2 Arthur Southwood - Melba Southwood 1 Dave Stamp - Ijsklont   110 0 100 2= by E Lead A

N
S
Board 3
100
100%
K6
Q972
Q10
Q8654
9
14 9
8
Linda Hitchen
Wynn Sutherland
  
QJ53
KJ4
K9
KJ97

A853
AJ876532
10
5-1 by E Lead A
par:-800.6X-4 (N)
 NT
N  7  1  3  8  3
S  7  1  3  8  3
E  612  9  510
W  612  9  510
Double Dummy Solv:Bo Haglund
 
A1098742
106
4
A32
 
WNES
   3
4
5
100(1) 100%-1370(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 4 Linda Hitchen - Wynn Sutherland 100   100 0 5-1 by E Lead A
2 Arthur Southwood - Melba Southwood 1 Dave Stamp - Ijsklont   1370 0 100 6= by E Lead A
N
S
Board 4
-200
0%
KJ763
82
Q108
1062
6
10 8
16
Linda Hitchen
Wynn Sutherland
  
A
K6543
J95
Q954
9854
AJ107
K763
7
3-2 by S Lead A
par:-140.3 (E)
 NT
N  8  5  4  8  7
S  8  5  4  8  7
E  5  7  9  4  6
W  5  7  9  4  6
Double Dummy Solv:Bo Haglund
 
Q102
Q9
A42
AKJ83
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Arthur Southwood - Melba Southwood 1 Dave Stamp - Ijsklont 110   100 0 2= by N Lead 7
3 Heather Carr - Mary Carter 4 Linda Hitchen - Wynn Sutherland   200 0 100 3-2 by S Lead A

N
S
Board 5
-110
100%
Q653
K1096
1097
A2
9
10 15
6
Linda Hitchen
Wynn Sutherland
  
J942
A75
QJ65
Q8
A7
QJ43
A4
KJ754
2+1 by E Lead 2
par:-120.1NT+1 (E)
 NT
N  4  6  5  6  5
S  4  6  5  6  5
E  8  7  8  7  8
W  8  7  8  7  8
Double Dummy Solv:Bo Haglund
 
K108
82
K832
10963
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 4 Linda Hitchen - Wynn Sutherland   110 100 0 2+1 by E Lead 2
2 Arthur Southwood - Melba Southwood 1 Dave Stamp - Ijsklont   400 0 100 3NT= by W Lead T
N
S
Board 6
-170
0%
1098
J92
AKQ7
J73
11
5 15
9
Linda Hitchen
Wynn Sutherland
  
J4
107
986543
A84
AQ76
AKQ865
10
106
1+3 by E Lead 2
par:-500.5X-3 (N)
 NT
N  8  6  3  5  5
S  8  6  3  5  5
E  4  710  7  8
W  4  710  7  8
Double Dummy Solv:Bo Haglund
 
K532
43
J2
KQ952
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Arthur Southwood - Melba Southwood 1 Dave Stamp - Ijsklont   140 100 0 1+2 by E Lead K
3 Heather Carr - Mary Carter 4 Linda Hitchen - Wynn Sutherland   170 0 100 1+3 by E Lead 2

N
S
Board 7
150
50%
6432
K1096
J10
Q93
6
11 6
17
Dave Stamp
ijsklont
  
105
QJ
AK985
J1075
Q987
A872
73
642
2NT+1 by N Lead 9
par:110.1+1 (N)
 NT
N  7  7  8  6  7
S  7  7  8  6  7
E  6  6  5  5  5
W  6  6  5  5  5
Double Dummy Solv:Bo Haglund
 
AKJ
543
Q642
AK8
 
WNES
   1
1N 2N
150(2) 50%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Linda Hitchen - Wynn Sutherland 2 Arthur Southwood - Melba Southwood 150   50 50 2NT+1 by S Lead 5
3 Heather Carr - Mary Carter 1 Dave Stamp - Ijsklont 150   50 50 2NT+1 by N Lead 9
N
S
Board 8
460
100%
A5
AK10
AKQ105
1065
20
6 7
7
Dave Stamp
ijsklont
  
106
9763
J94
KQ98
QJ9872
82
73
A43
3NT+2 by N Lead 9
par:420.4 (N)
 NT
N  81010  6  9
S  81010  6  9
E  4  2  2  7  2
W  5  2  2  7  2
Double Dummy Solv:Bo Haglund
 
K43
QJ54
862
J72
 
WNES
2 2
2N 3N
460(1) 100%170(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 1 Dave Stamp - Ijsklont 460   100 0 3NT+2 by N Lead 9
4 Linda Hitchen - Wynn Sutherland 2 Arthur Southwood - Melba Southwood 170   0 100 3+1 by S Lead T

N
S
Board 9
100
100%
AQJ
K954
K32
J82
14
5 14
7
Dave Stamp
ijsklont
  
K1096
832
1075
Q109
43
A107
AQ9864
A7
2-1 by E Lead 4
par:110.1+1 (N)
 NT
N  9  6  8  8  6
S  9  6  8  8  6
E  4  7  5  5  6
W  4  7  5  5  6
Double Dummy Solv:Bo Haglund
 
8752
QJ6
J
K6543
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 1 Dave Stamp - Ijsklont 100   100 0 2-1 by E Lead 4
4 Linda Hitchen - Wynn Sutherland 2 Arthur Southwood - Melba Southwood   90 0 100 2= by E Lead 3
N
S
Board 10
110
0%
AK964
105
A86
K93
14
9 10
7
Dave Stamp
ijsklont
  
8732
K7
53
AQ842
J
QJ942
KQ1072
J5
2= by N Lead K
par:120.1NT+1 (N)
 NT
N  7  5  5  8  8
S  6  5  5  8  8
E  6  7  7  5  5
W  6  7  7  5  5
Double Dummy Solv:Bo Haglund
 
Q105
A863
J94
1076
 
WNES
  
12
2
140(1) 100%110(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Linda Hitchen - Wynn Sutherland 2 Arthur Southwood - Melba Southwood 140   100 0 2+1 by N Lead K
3 Heather Carr - Mary Carter 1 Dave Stamp - Ijsklont 110   0 100 2= by N Lead K

N
S
Board 11
-100
50%
J762
J103
8652
87
2
7 17
14
Dave Stamp
ijsklont
  
A104
9875
Q103
J42
85
AK62
AK4
K1095
1NT-2 by S Lead 9
par:-140.3 (E)
 NT
N  5  6  4  7  5
S  5  6  4  7  5
E  8  7  9  6  8
W  8  7  9  6  8
Double Dummy Solv:Bo Haglund
 
KQ93
Q4
J97
AQ63
 
WNES
   1N
-100(2) 50%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 1 Dave Stamp - Ijsklont   100 50 50 1NT-2 by S Lead 9
4 Linda Hitchen - Wynn Sutherland 2 Arthur Southwood - Melba Southwood   100 50 50 1NTX-1 by S Lead 9
N
S
Board 12
620
100%
A9832

K1087
AK98
14
8 10
8
Dave Stamp
ijsklont
  
K105
64
Q96
QJ1076
Q4
AQJ93
J42
543
4= by N Lead 2
par:620.4 (N)
 NT
N  7  9  810  8
S  7  9  810  8
E  6  4  4  3  5
W  6  4  4  3  5
Double Dummy Solv:Bo Haglund
 
J76
K108752
A53
2
 
WNES
1 2
3 3
4
620(1) 100%300(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 1 Dave Stamp - Ijsklont 620   100 0 4= by N Lead 2
4 Linda Hitchen - Wynn Sutherland 2 Arthur Southwood - Melba Southwood 300   0 100 2X-2 by E Lead 2

N
S
Board 13
120
0%
A53
A542
J8
AQJ4
16
7 9
8
Arthur Southwood
Melba Southwood
  
8762
K73
A102
732
J104
1098
KQ53
K96
1NT+1 by N Lead 9
par:120.1NT+1 (N)
 NT
N  9  7  8  8  8
S  9  7  8  8  8
E  4  6  4  5  5
W  4  6  4  5  5
Double Dummy Solv:Bo Haglund
 
KQ9
QJ6
9764
1085
 
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dave Stamp - Ijsklont 4 Linda Hitchen - Wynn Sutherland 150   100 0 1NT+2 by N Lead K
3 Heather Carr - Mary Carter 2 Arthur Southwood - Melba Southwood 120   0 100 1NT+1 by N Lead 9
N
S
Board 14
-420
0%
QJ109754
32
4
975
3
13 9
15
Arthur Southwood
Melba Southwood
  
K82
KJ1084
KQ6
J4
3
765
AJ972
A1082
4= by W Lead 4
par:-430.4NT (E)
 NT
N  4  3  3  8  3
S  4  3  3  8  4
E  71010  410
W  710  9  4  9
Double Dummy Solv:Bo Haglund
 
A6
AQ9
10853
KQ63
 
WNES
   1
1123
334
50(1) 100%-420(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dave Stamp - Ijsklont 4 Linda Hitchen - Wynn Sutherland 50   100 0 3-1 by W Lead 4
3 Heather Carr - Mary Carter 2 Arthur Southwood - Melba Southwood   420 0 100 4= by W Lead 4

N
S
Board 15
650
0%

Q94
AK9872
9863
9
11 5
15
Arthur Southwood
Melba Southwood
  
J876
8
Q653
AKJ10
K10932
653
104
Q42
4+1 by S Lead A
par:650.5 (N)
 NT
N  8  911  6  9
S  8  911  6  9
E  5  4  1  7  3
W  5  4  1  7  3
Double Dummy Solv:Bo Haglund
 
AQ54
AKJ1072
J
75
 
WNES
   1
X1N23
34
800(1) 100%650(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dave Stamp - Ijsklont 4 Linda Hitchen - Wynn Sutherland 800   100 0 4X-4 by E Lead J
3 Heather Carr - Mary Carter 2 Arthur Southwood - Melba Southwood 650   0 100 4+1 by S Lead A
N
S
Board 16
110
50%
754
K92
Q652
973
5
11 6
18
Arthur Southwood
Melba Southwood
  
K6
J10764
103
AK64
J109
853
A97
J1052
2= by S Lead A
par:140.2+1 (N)
 NT
N  5  9  5  9  7
S  5  9  5  9  7
E  8  4  8  4  6
W  8  4  8  4  6
Double Dummy Solv:Bo Haglund
 
AQ832
AQ
KJ84
Q8
 
WNES
1
2 2
110(2) 50%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Heather Carr - Mary Carter 2 Arthur Southwood - Melba Southwood 110   50 50 2= by S Lead A
1 Dave Stamp - Ijsklont 4 Linda Hitchen - Wynn Sutherland 110   50 50 1+1 by S Lead T

N
S
Board 17
-430
0%
103
J1032
KJ763
J9
6
9 16
9
Arthur Southwood
Melba Southwood
  
AJ872
9854
2
A72
K5
AQ6
Q984
KQ43
3NT+1 by E Lead 4
par:-140.1+2 (E)
 NT
N  4  6  4  3  4
S  4  6  4  4  4
E  9  7  9  9  8
W  9  7  9  9  8
Double Dummy Solv:Bo Haglund
 
Q964
K7
A105
10865
 
WNES
  1
1 1N
3N
-400(1) 100%-430(1) 0%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dave Stamp - Ijsklont 4 Linda Hitchen - Wynn Sutherland   400 100 0 3NT= by E Lead T
3 Heather Carr - Mary Carter 2 Arthur Southwood - Melba Southwood   430 0 100 3NT+1 by E Lead 4
N
S
Board 18
-480
50%
104
A8
84
KJ96542
8
6 20
6
Arthur Southwood
Melba Southwood
  
86
QJ10954
K9653
AK32
K32
A
AQ1083
4+2 by E Lead 7
par:-980.6 (E)
 NT
N  4  4  1  5  2
S  4  4  1  5  2
E  8  912  810
W  8  912  810
Double Dummy Solv:Bo Haglund
 
QJ975
76
QJ1072
7
 
WNES
  2N*
3 3
4
-480(2) 50%
Show play
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dave Stamp - Ijsklont 4 Linda Hitchen - Wynn Sutherland   480 50 50 4+2 by E Lead 7
3 Heather Carr - Mary Carter 2 Arthur Southwood - Melba Southwood   480 50 50 4+2 by E Lead 7