Hands of game 2023-05-05 #78313 Lancashire LOP Restricted - NGS  -

Board

1
J95
AK10742
K974
11
7 10
12
Pamela Houghton
Sharman Fanning
 
Q4
Q1084
J3
Q10865		 AJ9652
A63
85
J3
par:400.3NT (N)
 NT
N  711  7  8  9
S  711  8  8  9
E  6  2  5  5  4
W  6  2  5  5  4
Double Dummy Solv:Bo Haglund
 
K10873
K72
Q96
A2
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 David Harris - Joyce Butterfield 2 Claush - Tash1 400   100 0 3NT= by S Lead Q
6 Hyldalo - Ray Emanuel 5 Brian Frew - Jack Lowe 150   25 75 2NT+1 by S Lead 6
4 Pamela Houghton - Sharman Fanning 1 Arthur Southwood - Melba Southwood 150   25 75 2-3 by E Lead 6

Board

2

 4
QJ109542
Q
AQJ7
12
3 15
10
David Harris
Joyce Butterfield
 
Q1097
8
J109743
98		 AJ63
A3
K2
K6532
par:100.4X-1 (E)
 NT
N  5  310  4  8
S  5  310  4  8
E  710  3  9  4
W  710  3  9  4
Double Dummy Solv:Bo Haglund
 
K852
K76
A865
104
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Pamela Houghton - Sharman Fanning 1 Arthur Southwood - Melba Southwood 650   100 0 5= by N Lead A
3 David Harris - Joyce Butterfield 2 Claush - Tash1 200   50 50 3+2 by N Lead 3
6 Hyldalo - Ray Emanuel 5 Brian Frew - Jack Lowe   100 0 100 5-1 by N Lead A

Board

3

 Q83
1095
J9
J8432
4
12 18
6
Pamela Houghton
Sharman Fanning
 
A10752
J
Q64
KQ105
AK632
AK103
A976
par:-1370.6 (E)
 NT
N  1  1  2  4  2
S  1  1  2  4  2
E121211  911
W121111  911
Double Dummy Solv:Bo Haglund
 
KJ964
Q874
8752
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 David Harris - Joyce Butterfield 2 Claush - Tash1 200   100 0 6X-1 by E Lead 2
6 Hyldalo - Ray Emanuel 5 Brian Frew - Jack Lowe   690 25 75 3NT+3 by E Lead 4
4 Pamela Houghton - Sharman Fanning 1 Arthur Southwood - Melba Southwood   690 25 75 3NT+3 by E Lead 2

Board

4

 KJ83
J108
Q1086
J9
8
12 10
10
Pamela Houghton
Sharman Fanning
 
A52
754
A7
A8764		 96
A96
KJ9542
Q2
par:140.3 (N)
 NT
N  5  4  7  9  5
S  5  4  7  9  5
E  7  9  5  4  6
W  7  9  5  4  6
Double Dummy Solv:Bo Haglund
 
Q1074
KQ32
3
K1053
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Pamela Houghton - Sharman Fanning 1 Arthur Southwood - Melba Southwood 100   75 25 3NT-1 by W Lead 3
6 Hyldalo - Ray Emanuel 5 Brian Frew - Jack Lowe 100   75 25 2-1 by W Lead 8
3 David Harris - Joyce Butterfield 2 Claush - Tash1   90 0 100 1NT= by W Lead 3

Board

5

 98
A1052
854
A987
8
7 10
15
Pamela Houghton
Sharman Fanning
 
AQ1032
9
J32
10654		 K7654
KQ4
Q97
32
par:100.3X-1 (E)
 NT
N  8  8  9  5  7
S  8  8  9  5  7
E  5  4  4  8  6
W  5  4  4  8  6
Double Dummy Solv:Bo Haglund
 
J
J8763
AK106
KQJ
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Arthur Southwood - Melba Southwood 2 Claush - Tash1 300   100 0 4X-2 by E Lead K
6 Hyldalo - Ray Emanuel 3 David Harris - Joyce Butterfield   100 25 75 4-1 by S Lead 4
4 Pamela Houghton - Sharman Fanning 5 Brian Frew - Jack Lowe   100 25 75 4-1 by S Lead A

Board

6

 K1086
75
J54
AQ105
10
2 15
13
Arthur Southwood
Melba Southwood
 
J542
10642
1092
J6		 AQ9
83
AQ76
K974
par:400.3NT (N)
 NT
N  8  7  9  7  9
S  7  6  8  6  8
E  5  6  4  6  4
W  5  6  4  6  4
Double Dummy Solv:Bo Haglund
 
73
AKQJ9
K83
832
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Arthur Southwood - Melba Southwood 2 Claush - Tash1 140   100 0 2+1 by S Lead J
4 Pamela Houghton - Sharman Fanning 5 Brian Frew - Jack Lowe 120   50 50 1NT+1 by N Lead 8
6 Hyldalo - Ray Emanuel 3 David Harris - Joyce Butterfield   50 0 100 2-1 by S Lead T

Board

7

 853
Q76
2
A109632
6
12 11
11
Arthur Southwood
Melba Southwood
 
J942
A
KJ543
K87		 K107
J108
AQ109
J54
par:500.5X-2 (E)
 NT
N  8  310  6  6
S  8  310  6  6
E  4  9  3  6  6
W  4  9  3  6  6
Double Dummy Solv:Bo Haglund
 
AQ6
K95432
876
Q
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Arthur Southwood - Melba Southwood 2 Claush - Tash1   110 75 25 2= by W Lead 6
4 Pamela Houghton - Sharman Fanning 5 Brian Frew - Jack Lowe   110 75 25 3= by W Lead 2
6 Hyldalo - Ray Emanuel 3 David Harris - Joyce Butterfield   200 0 100 4-2 by S Lead 2

Board

8

 Q985
KQ2
J8
K532
11
15 8
6
Arthur Southwood
Melba Southwood
 
K104
AJ3
Q1064
AJ9		 AJ7
1076
K9753
86
par:-430.3NT+1 (W)
 NT
N  6  3  5  5  3
S  6  3  5  5  3
E  7  9  8  8  9
W  710  8  810
Double Dummy Solv:Bo Haglund
 
632
9854
A2
Q1074
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Hyldalo - Ray Emanuel 3 David Harris - Joyce Butterfield   110 100 0 2+1 by W Lead 2
4 Pamela Houghton - Sharman Fanning 5 Brian Frew - Jack Lowe   150 50 50 2NT+1 by W Lead 5
1 Arthur Southwood - Melba Southwood 2 Claush - Tash1   180 0 100 1NT+3 by W Lead 5

Board

9

 976
K109
9762
K87
6
12 16
6
Arthur Southwood
Melba Southwood
 
QJ54
A873
KQ108
9		 AK2
J65
A3
A6432
par:-1430.6 (E)
 NT
N  3  3  2  1  3
S  3  3  2  1  3
E1010111210
W1010111210
Double Dummy Solv:Bo Haglund
 
1083
Q42
J54
QJ105
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Arthur Southwood - Melba Southwood 6 Hyldalo - Ray Emanuel   630 50 50 3NT+1 by E Lead Q
4 Pamela Houghton - Sharman Fanning 2 Claush - Tash1   630 50 50 3NT+1 by W Lead 9
5 Brian Frew - Jack Lowe 3 David Harris - Joyce Butterfield   630 50 50 3NT+1 by W Lead 7

Board

10

 QJ10
KQ108
1076
954
8
2 14
16
Arthur Southwood
Melba Southwood
 
974
76
Q8542
632		 K632
943
KJ93
AK
par:650.4+1 (N)
 NT
N10  611  7  8
S10  611  7  8
E  2  7  2  6  5
W  2  7  2  6  5
Double Dummy Solv:Bo Haglund
 
A85
AJ52
A
QJ1087
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Arthur Southwood - Melba Southwood 6 Hyldalo - Ray Emanuel 200   100 0 1NT-2 by E Lead Q
4 Pamela Houghton - Sharman Fanning 2 Claush - Tash1 130   50 50 3+1 by S Lead 2
5 Brian Frew - Jack Lowe 3 David Harris - Joyce Butterfield 100   0 100 2-1 by W Lead Q

Board

11

 KQJ8
J9843
A93
7
11
14 9
6
Arthur Southwood
Melba Southwood
 
A93
K7
K542
A852		 74
A1065
Q876
K94
par:-110.3 (E)
 NT
N  5  4  6  7  6
S  5  4  6  7  6
E  8  9  7  6  7
W  8  9  7  6  7
Double Dummy Solv:Bo Haglund
 
10652
Q2
J10
QJ1063
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Arthur Southwood - Melba Southwood 6 Hyldalo - Ray Emanuel 100   100 0 2NT-2 by W Lead K
5 Brian Frew - Jack Lowe 3 David Harris - Joyce Butterfield   50 50 50 2-1 by S Lead 4
4 Pamela Houghton - Sharman Fanning 2 Claush - Tash1   150 0 100 1NT+2 by W Lead 4

Board

12

 J87543
Q82
QJ
K4
9
21 6
4
David Harris
Joyce Butterfield
 
A
A
AK1083
AQ10863		 KQ92
J109764
94
9
par:-920.6 (E)
 NT
N  2  1  2  4  3
S  2  1  2  4  3
E111211  810
W111211  810
Double Dummy Solv:Bo Haglund
 
106
K53
7652
J752
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Arthur Southwood - Melba Southwood 6 Hyldalo - Ray Emanuel   170 100 0 3+3 by W Lead 8
5 Brian Frew - Jack Lowe 3 David Harris - Joyce Butterfield   420 50 50 4= by W Lead Q
4 Pamela Houghton - Sharman Fanning 2 Claush - Tash1   460 0 100 3NT+2 by W Lead 5

Board

13

 Q832
6
KQJ632
104
8
12 10
10
Arthur Southwood
Melba Southwood
 
764
Q2
A1097
KQJ8		 J
AJ107
84
A97632
par:200.5X-1 (E)
 NT
N  3  8  810  5
S  3  8  810  5
E10  5  5  3  8
W10  4  5  3  8
Double Dummy Solv:Bo Haglund
 
AK1095
K98543
5
5
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Claush - Tash1 6 Hyldalo - Ray Emanuel 170   100 0 2+2 by N Lead 8
4 Pamela Houghton - Sharman Fanning 3 David Harris - Joyce Butterfield   130 50 50 3+1 by E Lead A
5 Brian Frew - Jack Lowe 1 Arthur Southwood - Melba Southwood   200 0 100 2-2 by S Lead K

Board

14

 AQ84
9864
863
104
6
7 10
17
Arthur Southwood
Melba Southwood
 
10965
Q75
KQ4
963		 J3
KJ32
AJ9
8752
par:120.1NT+1 (N)
 NT
N  8  8  7  8  8
S  8  8  7  8  8
E  5  5  6  4  5
W  5  5  6  4  5
Double Dummy Solv:Bo Haglund
 
K72
A10
10752
AKQJ
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Claush - Tash1 6 Hyldalo - Ray Emanuel 150   100 0 1NT+2 by S Lead 5
5 Brian Frew - Jack Lowe 1 Arthur Southwood - Melba Southwood 120   25 75 2NT= by S Lead 9
4 Pamela Houghton - Sharman Fanning 3 David Harris - Joyce Butterfield 120   25 75 2NT= by S Lead 5

Board

15

 AJ1086
Q843
Q6
KJ
13
10 11
6
David Harris
Joyce Butterfield
 
Q9
KJ97
A8752
103		 54
A10
J3
AQ87542
par:-130.2+2 (E)
 NT
N  3  5  6  7  3
S  2  5  6  6  2
E10  8  7  5  8
W10  8  7  5  8
Double Dummy Solv:Bo Haglund
 
K732
652
K1094
96
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Claush - Tash1 6 Hyldalo - Ray Emanuel   130 50 50 4= by E Lead 3
4 Pamela Houghton - Sharman Fanning 3 David Harris - Joyce Butterfield   130 50 50 4= by E Lead 2
5 Brian Frew - Jack Lowe 1 Arthur Southwood - Melba Southwood   130 50 50 4= by E Lead 2

Board

16

 K10
AJ10652
9
KQ92
13
17 2
8
David Harris
Joyce Butterfield
 
J98732
KQ
AK
A106		 54
984
Q108532
74
par:400.3NT (N)
 NT
N10  5  9  6  9
S10  5  9  6  9
E  3  8  3  7  4
W  3  8  3  7  4
Double Dummy Solv:Bo Haglund
 
AQ6
73
J764
J853
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Pamela Houghton - Sharman Fanning 3 David Harris - Joyce Butterfield 140   100 0 3= by N Lead 5
2 Claush - Tash1 6 Hyldalo - Ray Emanuel 130   50 50 3+1 by N Lead 4
5 Brian Frew - Jack Lowe 1 Arthur Southwood - Melba Southwood   50 0 100 3-1 by N Lead 5

Board

17

 A10952
7
A95
K1086
11
10 14
5
David Harris
Joyce Butterfield
 
Q8
K652
K6
Q9754		 K7643
A943
QJ
A3
par:100.3X-1 (E)
 NT
N  6  9  5  6  7
S  6  9  5  6  7
E  7  4  8  7  5
W  7  4  8  7  6
Double Dummy Solv:Bo Haglund
 
J
QJ108
1087432
J2
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 David Harris - Joyce Butterfield 1 Arthur Southwood - Melba Southwood 150   100 0 4-3 by E Lead 3
2 Claush - Tash1 5 Brian Frew - Jack Lowe 110   50 50 1+1 by N Lead Q
4 Pamela Houghton - Sharman Fanning 6 Hyldalo - Ray Emanuel   50 0 100 2-1 by N Lead A

Board

18

 Q64
985
Q10964
Q2
6
15 9
10
David Harris
Joyce Butterfield
 
8
AKQJ6
J52
A983		 AJ105
7432
8
KJ106
par:-980.6 (E)
 NT
N  1  7  1  7  3
S  1  7  1  7  3
E12  512  6  8
W12  512  6  8
Double Dummy Solv:Bo Haglund
 
K9732
10
AK73
754
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Claush - Tash1 5 Brian Frew - Jack Lowe 50   100 0 4-1 by W Lead 6
4 Pamela Houghton - Sharman Fanning 6 Hyldalo - Ray Emanuel   170 50 50 3+1 by W Lead 4
3 David Harris - Joyce Butterfield 1 Arthur Southwood - Melba Southwood   450 0 100 4+1 by W Lead 6

Board

19

 AQ863
Q72
8
J1065
9
9 9
13
Arthur Southwood
Melba Southwood
 
9
8643
K954
AQ73		 K1052
K95
632
K84
par:420.4 (N)
 NT
N  8  8  710  8
S  8  8  710  8
E  5  4  5  3  5
W  5  4  5  3  5
Double Dummy Solv:Bo Haglund
 
J74
AJ10
AQJ107
92
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 David Harris - Joyce Butterfield 1 Arthur Southwood - Melba Southwood 140   100 0 2+1 by S Lead 6
2 Claush - Tash1 5 Brian Frew - Jack Lowe 120   50 50 1NT+1 by S Lead 3
4 Pamela Houghton - Sharman Fanning 6 Hyldalo - Ray Emanuel   100 0 100 3-2 by S Lead 9

Board

20

 10
109753
A853
Q84
6
7 15
12
Arthur Southwood
Melba Southwood
 
5
Q62
KJ97642
J9		 AQ872
AK84
Q10
73
par:-130.4 (E)
 NT
N10  3  5  8  7
S10  3  5  8  7
E  210  8  4  5
W  210  7  4  5
Double Dummy Solv:Bo Haglund
 
KJ9643
J

AK10652
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Claush - Tash1 5 Brian Frew - Jack Lowe 790   100 0 4X= by S Lead J
4 Pamela Houghton - Sharman Fanning 6 Hyldalo - Ray Emanuel 200   50 50 3NT-2 by E Lead 6
3 David Harris - Joyce Butterfield 1 Arthur Southwood - Melba Southwood   600 0 100 3NT= by E Lead A

PodioProgressivo not implemented for mySql

  • Progressive Podium for game:2023-05-05 #78313 Lancashire LOP Restricted - NGS
    		•  
    BoardN Codice1 Player1 Codice2 Player2
    20 Arthur174   Arthur Southwood claras92   Melba Southwood

    PodioProgressivo not implemented for mySql

  • Progressive Podium (with average) for game:2023-05-05 #78313 Lancashire LOP Restricted - NGS
    		•  
    BoardN Codice1 Player1 Codice2 Player2