Hands of game 2023-03-12 #49119 Lancashire Online LOP Open Pairs -

Board

1

 K9742
A5
AK3
Q83
16
4 15
5
Monica Cartwright
Sue Woodcock
 
1083
109
9752
A542		 A5
KJ872
QJ64
KJ
par:140.3 (N)
 NT
N  8  5  6  9  7
S  7  4  6  8  7
E  5  8  7  4  6
W  5  8  7  4  6
Double Dummy Solv:Bo Haglund
 
QJ6
Q643
108
10976
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
7 Jack Lowe - Terry Potter 3 Joan Cann - Joyce Truffas 150   100 0 2NT-3 by E Lead Q
6 Irene Bowers - Wynn Sutherland 5 Bill Wattleworth - Peter Richmond 140   75 25 2+1 by N Lead Q
8 Alan Frost - Joanne Evans 1 Linda Smith - Michael Tomlinson 50   50 50 2-1 by E Lead Q
2 Alan Whittam - Paul Evans 4 Colin Beesley - Kep Simcox   50 12.5 87.5 3-1 by N Lead Q
9 Monica Cartwright - Sue Woodcock 10 Neil Kenyon - Vinay Bhushan   50 12.5 87.5 3-1 by N Lead 4

Board

2

 5
AQJ5
Q108642
102
9
6 9
16
Monica Cartwright
Sue Woodcock
 
QJ10972
K973
73
7		 8643
108
AK9
Q543
par:660.5NT (N)
 NT
N111010  511
S111010  511
E  2  2  3  8  2
W  2  2  3  8  2
Double Dummy Solv:Bo Haglund
 
AK
642
J5
AKJ986
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
9 Monica Cartwright - Sue Woodcock 10 Neil Kenyon - Vinay Bhushan 660   100 0 3NT+2 by S Lead Q
6 Irene Bowers - Wynn Sutherland 5 Bill Wattleworth - Peter Richmond 300   75 25 4X-2 by W Lead T
8 Alan Frost - Joanne Evans 1 Linda Smith - Michael Tomlinson 100   37.5 62.5 4-2 by W Lead T
2 Alan Whittam - Paul Evans 4 Colin Beesley - Kep Simcox 100   37.5 62.5 3X-1 by W Lead T
7 Jack Lowe - Terry Potter 3 Joan Cann - Joyce Truffas   200 0 100 3NT-2 by S Lead Q

Board

3

 54
54
Q7
KQ98742
7
14 6
13
Monica Cartwright
Sue Woodcock
 
KJ32
Q10963
A
A65		 106
AJ7
1098542
J3
par:-100.4X-1 (S)
 NT
N  8  5  4  6  5
S  9  5  4  7  6
E  4  7  9  6  6
W  4  7  8  6  6
Double Dummy Solv:Bo Haglund
 
AQ987
K82
KJ63
10
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
8 Alan Frost - Joanne Evans 5 Bill Wattleworth - Peter Richmond 130   75 25 3+1 by N Lead 3
10 Neil Kenyon - Vinay Bhushan 1 Linda Smith - Michael Tomlinson 130   75 25 4= by N Lead A
7 Jack Lowe - Terry Potter 4 Colin Beesley - Kep Simcox 130   75 25 4= by N Lead A
2 Alan Whittam - Paul Evans 6 Irene Bowers - Wynn Sutherland   100 25 75 3NT-2 by S Lead 9
9 Monica Cartwright - Sue Woodcock 3 Joan Cann - Joyce Truffas   110 0 100 2= by W Lead 5

Board

4

 K4
K104
AQJ642
82
13
7 11
9
Monica Cartwright
Sue Woodcock
 
J83
Q52
10953
A53		 AQ107
AJ9873
8
106
par:-620.4 (E)
 NT
N  8  8  3  4  6
S  8  8  3  2  2
E  4  410  7  7
W  4  410  7  7
Double Dummy Solv:Bo Haglund
 
9652
6
K7
KQJ974
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Alan Whittam - Paul Evans 6 Irene Bowers - Wynn Sutherland 130   87.5 12.5 4= by N Lead A
9 Monica Cartwright - Sue Woodcock 3 Joan Cann - Joyce Truffas 130   87.5 12.5 3+1 by N Lead A
8 Alan Frost - Joanne Evans 5 Bill Wattleworth - Peter Richmond 100   50 50 4-1 by W Lead 8
7 Jack Lowe - Terry Potter 4 Colin Beesley - Kep Simcox   100 25 75 3NT-1 by N Lead 3
10 Neil Kenyon - Vinay Bhushan 1 Linda Smith - Michael Tomlinson   140 0 100 3= by E Lead K

Board

5

 6
A84
QJ973
A984
11
14 7
8
Monica Cartwright
Sue Woodcock
 
103
Q2
AK65
KQ765		 KQJ9754
J97
1082
par:-140.3 (E)
 NT
N  9  8  9  3  8
S  9  7  8  3  8
E  4  5  3  9  5
W  4  5  4  9  5
Double Dummy Solv:Bo Haglund
 
A82
K10653
4
J1032
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
9 Monica Cartwright - Sue Woodcock 1 Linda Smith - Michael Tomlinson 50   100 0 3-1 by E Lead 4
8 Alan Frost - Joanne Evans 2 Alan Whittam - Paul Evans   170 75 25 3+1 by E Lead 4
3 Joan Cann - Joyce Truffas 4 Colin Beesley - Kep Simcox   420 37.5 62.5 4= by E Lead 4
7 Jack Lowe - Terry Potter 6 Irene Bowers - Wynn Sutherland   420 37.5 62.5 4= by E Lead 4
10 Neil Kenyon - Vinay Bhushan 5 Bill Wattleworth - Peter Richmond   800 0 100 5X-3 by N Lead K

Board

6

 J84
74
A105
AJ962
10
12 10
8
Monica Cartwright
Sue Woodcock
 
Q732
AK82
632
K8		 A106
J10
QJ984
Q73
par:-110.2+1 (E)
 NT
N  7  4  6  5  6
S  7  4  6  5  6
E  6  9  7  8  6
W  6  9  7  8  7
Double Dummy Solv:Bo Haglund
 
K95
Q9653
K7
1054
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Joan Cann - Joyce Truffas 4 Colin Beesley - Kep Simcox   90 100 0 1NT= by W Lead 6
9 Monica Cartwright - Sue Woodcock 1 Linda Smith - Michael Tomlinson   110 75 25 3= by E Lead 5
10 Neil Kenyon - Vinay Bhushan 5 Bill Wattleworth - Peter Richmond   120 37.5 62.5 1NT+1 by W Lead 6
8 Alan Frost - Joanne Evans 2 Alan Whittam - Paul Evans   120 37.5 62.5 1NT+1 by W Lead 6
7 Jack Lowe - Terry Potter 6 Irene Bowers - Wynn Sutherland   130 0 100 3+1 by E Lead T

Board

7

 K2
KJ72
Q108653
8
9
20 6
5
Monica Cartwright
Sue Woodcock
 
A7
A95
A
AKJ7543
Q108643
KJ742
92
par:-1100.6X-4 (N)
 NT
N  1  4  1  8  1
S  1  3  1  8  1
E12  912  511
W11  912  511
Double Dummy Solv:Bo Haglund
 
QJ10986543

9
Q106
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
7 Jack Lowe - Terry Potter 8 Alan Frost - Joanne Evans   200 87.5 12.5 5X-1 by S Lead A
1 Linda Smith - Michael Tomlinson 5 Bill Wattleworth - Peter Richmond   200 87.5 12.5 5X-1 by S Lead A
3 Joan Cann - Joyce Truffas 6 Irene Bowers - Wynn Sutherland   620 37.5 62.5 5+1 by W Lead K
9 Monica Cartwright - Sue Woodcock 4 Colin Beesley - Kep Simcox   620 37.5 62.5 5+1 by W Lead K
10 Neil Kenyon - Vinay Bhushan 2 Alan Whittam - Paul Evans   1430 0 100 6= by E Lead Q

Board

8

 97642
AKJ2
7
852
8
11 7
14
Monica Cartwright
Sue Woodcock
 
KQJ105
965
K964
Q		 83
Q104
J1083
A976
par:130.3+1 (N)
 NT
N10  6  8  7  6
S10  6  8  7  7
E  2  7  4  6  6
W  2  6  4  6  5
Double Dummy Solv:Bo Haglund
 
A
873
AQ52
KJ1043
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Smith - Michael Tomlinson 5 Bill Wattleworth - Peter Richmond 130   100 0 3+1 by S Lead K
3 Joan Cann - Joyce Truffas 6 Irene Bowers - Wynn Sutherland 110   75 25 3= by S Lead K
10 Neil Kenyon - Vinay Bhushan 2 Alan Whittam - Paul Evans   90 50 50 2= by W Lead A
9 Monica Cartwright - Sue Woodcock 4 Colin Beesley - Kep Simcox   100 25 75 5X-1 by S Lead K
7 Jack Lowe - Terry Potter 8 Alan Frost - Joanne Evans   120 0 100 1NT+1 by E Lead T

Board

9

 97

AQ86
AJ76542
11
10 9
10
Monica Cartwright
Sue Woodcock
 
Q106
Q1098753
K9
K		 J43
AK2
J10532
108
par:1400.7X-5 (E)
 NT
N13  8  5  9  6
S13  8  5  9  6
E  0  5  8  3  2
W  0  5  8  4  2
Double Dummy Solv:Bo Haglund
 
AK852
J64
74
Q93
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Colin Beesley - Kep Simcox 6 Irene Bowers - Wynn Sutherland 800   100 0 5X-3 by W Lead 9
3 Joan Cann - Joyce Truffas 8 Alan Frost - Joanne Evans 650   75 25 5X+1 by N Lead A
1 Linda Smith - Michael Tomlinson 2 Alan Whittam - Paul Evans 420   50 50 5+1 by N Lead A
10 Neil Kenyon - Vinay Bhushan 7 Jack Lowe - Terry Potter 170   12.5 87.5 4+2 by N Lead A
9 Monica Cartwright - Sue Woodcock 5 Bill Wattleworth - Peter Richmond 170   12.5 87.5 3+3 by N Lead A

Board

10

 A63
K
KQ10762
Q84
14
7 5
14
Monica Cartwright
Sue Woodcock
 
Q10742
J9752
9
A9		 KJ5
10643
53
J1076
par:1370.6 (N)
 NT
N1112  6  710
S1112  6  710
E  2  1  7  6  1
W  2  1  7  6  1
Double Dummy Solv:Bo Haglund
 
98
AQ8
AJ84
K532
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Joan Cann - Joyce Truffas 8 Alan Frost - Joanne Evans 690   100 0 3NT+3 by S Lead 5
10 Neil Kenyon - Vinay Bhushan 7 Jack Lowe - Terry Potter 660   50 50 3NT+2 by S Lead 4
1 Linda Smith - Michael Tomlinson 2 Alan Whittam - Paul Evans 660   50 50 3NT+2 by S Lead 5
4 Colin Beesley - Kep Simcox 6 Irene Bowers - Wynn Sutherland 660   50 50 3NT+2 by S Lead 4
9 Monica Cartwright - Sue Woodcock 5 Bill Wattleworth - Peter Richmond 150   0 100 3+2 by N Lead 6

Board

11

 KJ107
K74
KJ93
Q8
13
10 8
9
Monica Cartwright
Sue Woodcock
 
Q952
QJ93
A5
J95		 4
A865
1084
A7643
par:-100.3X-1 (N)
 NT
N  4  8  5  8  7
S  4  8  5  8  7
E  9  4  8  5  6
W  9  4  8  5  6
Double Dummy Solv:Bo Haglund
 
A863
102
Q762
K102
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Smith - Michael Tomlinson 7 Jack Lowe - Terry Potter 140   100 0 3= by N Lead A
4 Colin Beesley - Kep Simcox 8 Alan Frost - Joanne Evans 120   62.5 37.5 1NT+1 by N Lead 4
3 Joan Cann - Joyce Truffas 10 Neil Kenyon - Vinay Bhushan 120   62.5 37.5 1NT+1 by N Lead 4
9 Monica Cartwright - Sue Woodcock 6 Irene Bowers - Wynn Sutherland   50 25 75 1NT-1 by N Lead 4
5 Bill Wattleworth - Peter Richmond 2 Alan Whittam - Paul Evans   140 0 100 2+1 by E Lead 2

Board

12

 QJ4
102
A9864
Q97
9
13 6
12
Linda Smith
Michael Tomlinson
 
K973
K65
1053
AK4		 1065
Q73
QJ2
J1085
par:140.1+2 (N)
 NT
N  7  8  9  8  8
S  7  9  9  8  8
E  5  4  4  4  5
W  5  4  4  5  5
Double Dummy Solv:Bo Haglund
 
A82
AJ984
K7
632
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Colin Beesley - Kep Simcox 8 Alan Frost - Joanne Evans 170   100 0 2+2 by S Lead 3
3 Joan Cann - Joyce Truffas 10 Neil Kenyon - Vinay Bhushan 140   75 25 2+1 by S Lead A
9 Monica Cartwright - Sue Woodcock 6 Irene Bowers - Wynn Sutherland 100   50 50 1NT-2 by W Lead 6
5 Bill Wattleworth - Peter Richmond 2 Alan Whittam - Paul Evans 50   12.5 87.5 1NT-1 by W Lead 6
1 Linda Smith - Michael Tomlinson 7 Jack Lowe - Terry Potter 50   12.5 87.5 1NT-1 by W Lead 6

Board

13

 A9652
73
K854
74
7
19 5
9
Linda Smith
Michael Tomlinson
 
Q7
A1042
AQ3
AQJ6		 4
Q9865
97
K10982
par:-200.4X-1 (N)
 NT
N  3  8  3  9  6
S  3  8  3  9  6
E10  410  4  7
W10  510  4  7
Double Dummy Solv:Bo Haglund
 
KJ1083
KJ
J1062
53
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Linda Smith - Michael Tomlinson 3 Joan Cann - Joyce Truffas 200   100 0 3NT-2 by W Lead 5
5 Bill Wattleworth - Peter Richmond 7 Jack Lowe - Terry Potter   620 50 50 4= by W Lead 3
4 Colin Beesley - Kep Simcox 10 Neil Kenyon - Vinay Bhushan   620 50 50 4= by W Lead 7
6 Irene Bowers - Wynn Sutherland 8 Alan Frost - Joanne Evans   620 50 50 4= by W Lead A
9 Monica Cartwright - Sue Woodcock 2 Alan Whittam - Paul Evans   650 0 100 4+1 by W Lead 7

Board

14

 J10
A10982
A103
986
9
6 12
13
Alan Whittam
Paul Evans
 
Q9742
764
542
A4		 A853
Q
KQJ6
7532
par:-100.3NTX-1 (N)
 NT
N  9  5  9  4  8
S  9  5  9  4  8
E  4  7  3  9  4
W  4  7  3  9  4
Double Dummy Solv:Bo Haglund
 
K6
KJ53
987
KQJ10
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Irene Bowers - Wynn Sutherland 8 Alan Frost - Joanne Evans 140   62.5 37.5 3= by N Lead K
4 Colin Beesley - Kep Simcox 10 Neil Kenyon - Vinay Bhushan 140   62.5 37.5 3= by N Lead K
1 Linda Smith - Michael Tomlinson 3 Joan Cann - Joyce Truffas 140   62.5 37.5 3= by N Lead A
5 Bill Wattleworth - Peter Richmond 7 Jack Lowe - Terry Potter 140   62.5 37.5 3= by N Lead K
9 Monica Cartwright - Sue Woodcock 2 Alan Whittam - Paul Evans   140 0 100 3= by W Lead A

Board

15

 86
J1092
984
Q1043
3
10 14
13
Alan Whittam
Paul Evans
 
AKQ10
76543
62
J9		 J97
K
AKQJ1075
82
par:-200.5X-1 (N)
 NT
N10  2  8  2  2
S10  2  8  2  2
E  210  510  4
W  210  510  4
Double Dummy Solv:Bo Haglund
 
5432
AQ8
3
AK765
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Alan Whittam - Paul Evans 7 Jack Lowe - Terry Potter   130 100 0 3+1 by E Lead A
9 Monica Cartwright - Sue Woodcock 8 Alan Frost - Joanne Evans   150 37.5 62.5 3+2 by E Lead A
6 Irene Bowers - Wynn Sutherland 10 Neil Kenyon - Vinay Bhushan   150 37.5 62.5 2+3 by E Lead A
5 Bill Wattleworth - Peter Richmond 3 Joan Cann - Joyce Truffas   150 37.5 62.5 2+3 by E Lead A
4 Colin Beesley - Kep Simcox 1 Linda Smith - Michael Tomlinson   150 37.5 62.5 3+2 by E Lead A

Board

16

 86
J10862
Q4
8543
3
13 15
9
Alan Whittam
Paul Evans
 
A109753

KJ106
AJ10		 KJ2
KQ97
A82
Q92
par:-2210.7 (E)
 NT
N  2  0  4  0  0
S  2  0  4  0  0
E1112  91312
W1112  91312
Double Dummy Solv:Bo Haglund
 
Q4
A543
9753
K76
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Bill Wattleworth - Peter Richmond 3 Joan Cann - Joyce Truffas   680 100 0 4+2 by W Lead 5
9 Monica Cartwright - Sue Woodcock 8 Alan Frost - Joanne Evans   690 75 25 3NT+3 by E Lead 7
6 Irene Bowers - Wynn Sutherland 10 Neil Kenyon - Vinay Bhushan   710 25 75 4+3 by W Lead J
4 Colin Beesley - Kep Simcox 1 Linda Smith - Michael Tomlinson   710 25 75 4+3 by W Lead J
2 Alan Whittam - Paul Evans 7 Jack Lowe - Terry Potter   710 25 75 4+3 by W Lead J

Board

17

 J95
Q932
AKQ1093
12
11 11
6
Alan Whittam
Paul Evans
 
KQ1082
8
872
AQ109		 A4
AK74
654
8652
par:-100.3X-1 (N)
 NT
N  3  6  8  4  2
S  3  6  8  4  3
E  9  5  4  7  7
W  9  5  4  7  7
Double Dummy Solv:Bo Haglund
 
763
J1065
J
KJ743
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
9 Monica Cartwright - Sue Woodcock 7 Jack Lowe - Terry Potter 300   100 0 5X-2 by W Lead A
8 Alan Frost - Joanne Evans 10 Neil Kenyon - Vinay Bhushan 100   62.5 37.5 4-2 by W Lead A
5 Bill Wattleworth - Peter Richmond 4 Colin Beesley - Kep Simcox 100   62.5 37.5 4-2 by W Lead A
6 Irene Bowers - Wynn Sutherland 1 Linda Smith - Michael Tomlinson   50 25 75 2-1 by S Lead K
2 Alan Whittam - Paul Evans 3 Joan Cann - Joyce Truffas   150 0 100 5-3 by S Lead K

Board

18

 K873
A2
62
A9742
11
7 10
12
Linda Smith
Michael Tomlinson
 
54
J1097654
A9
Q10		 A102
3
Q1087
KJ653
par:620.4 (N)
 NT
N  7  8  610  8
S  7  8  610  8
E  6  4  7  3  5
W  6  4  6  3  5
Double Dummy Solv:Bo Haglund
 
QJ96
KQ8
KJ543
8
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Bill Wattleworth - Peter Richmond 4 Colin Beesley - Kep Simcox 620   100 0 4= by S Lead J
2 Alan Whittam - Paul Evans 3 Joan Cann - Joyce Truffas 500   75 25 4X-3 by W Lead 6
8 Alan Frost - Joanne Evans 10 Neil Kenyon - Vinay Bhushan 120   50 50 2NT= by N Lead 3
6 Irene Bowers - Wynn Sutherland 1 Linda Smith - Michael Tomlinson   100 12.5 87.5 3-1 by S Lead J
9 Monica Cartwright - Sue Woodcock 7 Jack Lowe - Terry Potter   100 12.5 87.5 4-1 by S Lead Q

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    BoardN Codice1 Player1 Codice2 Player2
    18 lmspas72   Linda Smith Mt11   Michael Tomlinson

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  • Progressive Podium (with average) for game:2023-03-12 #49119 Lancashire Online LOP Open Pairs
    		•  
    BoardN Codice1 Player1 Codice2 Player2