Hands of game 2023-03-05 #18411 Lancashire Online LOP Open Pairs -

Board

1

 AKJ75
109432
9
105
8
15 11
6
Bill Wattleworth
Peter Richmond
 
83
KJ86
AK106
A62		 Q42
AQ7
4
QJ9743
par:-460.3NT+2 (E)
 NT
N  1  6  3  5  1
S  1  6  3  5  1
E11  7  9  711
W11  7  9  711
Double Dummy Solv:Bo Haglund
 
1096
5
QJ87532
K8
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Alan Whittam - Paul Evans 1 Dytria - Sturwies 100   100 0 5-2 by E Lead Q
2 Bill Wattleworth - Peter Richmond 5 Colin Beesley - Kep Simcox   150 50 50 4+1 by E Lead T
6 Alan Frost - Joanne Evans 3 Jack Lowe - Terry Potter   490 0 100 3NT+3 by W Lead A

Board

2

 Q
KQ10974
Q87
KJ2
13
10 6
11
Bill Wattleworth
Peter Richmond
 
J83
3
K1092
AQ653		 9652
AJ65
J54
107
par:600.3NT (N)
 NT
N  7  7  9  9  9
S  7  7  9  9  9
E  6  6  3  4  4
W  6  6  3  4  4
Double Dummy Solv:Bo Haglund
 
AK1074
82
A63
984
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 5 Colin Beesley - Kep Simcox 620   100 0 4= by N Lead T
4 Alan Whittam - Paul Evans 1 Dytria - Sturwies 170   50 50 2+2 by N Lead T
6 Alan Frost - Joanne Evans 3 Jack Lowe - Terry Potter 150   0 100 2NT+1 by N Lead T

Board

3

 J43
86
KQ
AKJ962
14
13 6
7
Bill Wattleworth
Peter Richmond
 
A986
AKQ752
3
53		 K10
93
J108765
Q104
par:-140.2+1 (E)
 NT
N  7  6  4  6  4
S  7  6  4  5  4
E  5  7  9  7  8
W  5  7  9  7  8
Double Dummy Solv:Bo Haglund
 
Q752
J104
A942
87
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 5 Colin Beesley - Kep Simcox   110 100 0 2= by W Lead A
4 Alan Whittam - Paul Evans 1 Dytria - Sturwies   170 50 50 2+2 by W Lead A
6 Alan Frost - Joanne Evans 3 Jack Lowe - Terry Potter   200 0 100 3-4 by S Lead A

Board

4

 Q1085
Q764
A10
J107
9
9 12
10
Bill Wattleworth
Peter Richmond
 
J6
AJ5
K732
8543		 743
K982
QJ6
AQ9
par:110.2 (N)
 NT
N  5  5  5  8  6
S  4  5  5  8  5
E  7  8  7  5  7
W  8  8  7  5  7
Double Dummy Solv:Bo Haglund
 
AK92
103
9854
K62
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 5 Colin Beesley - Kep Simcox 200   100 0 1NT-2 by E Lead 8
4 Alan Whittam - Paul Evans 1 Dytria - Sturwies 100   50 50 1NT-1 by W Lead 5
6 Alan Frost - Joanne Evans 3 Jack Lowe - Terry Potter   120 0 100 1NT+1 by E Lead T

Board

5

 J76

AQ7643
KQ43
12
4 10
14
Bill Wattleworth
Peter Richmond
 
K9
98632
5
J10965		 Q53
AJ10
K10982
72
par:620.4 (N)
 NT
N  7  9  810  9
S  7  9  810  9
E  5  4  5  2  4
W  6  4  5  3  4
Double Dummy Solv:Bo Haglund
 
A10842
KQ754
J
A8
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Alan Frost - Joanne Evans 4 Alan Whittam - Paul Evans 600   100 0 3NT= by S Lead J
2 Bill Wattleworth - Peter Richmond 3 Jack Lowe - Terry Potter   100 50 50 4-1 by S Lead J
5 Colin Beesley - Kep Simcox 1 Dytria - Sturwies   200 0 100 4-2 by S Lead 5

Board

6

 10986
K73
AKJ63
8
11
12 6
11
Bill Wattleworth
Peter Richmond
 
K54
QJ10
Q854
A105		 Q72
9864
2
KJ764
par:400.3NT (N)
 NT
N  510  7  9  9
S  510  7  9  9
E  8  3  6  3  4
W  8  3  6  3  4
Double Dummy Solv:Bo Haglund
 
AJ3
A52
1097
Q932
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 3 Jack Lowe - Terry Potter 200   100 0 3-2 by E Lead T
5 Colin Beesley - Kep Simcox 1 Dytria - Sturwies 110   50 50 2= by N Lead 2
6 Alan Frost - Joanne Evans 4 Alan Whittam - Paul Evans 100   0 100 1NT-1 by W Lead A

Board

7

 AK108
J9752
QJ5
K
14
12 6
8
Bill Wattleworth
Peter Richmond
 
543
A
A32
A97652		 J972
Q3
986
QJ83
par:500.4NTX-2 (E)
 NT
N  51010  7  5
S  51010  7  5
E  8  3  3  6  8
W  8  3  3  6  8
Double Dummy Solv:Bo Haglund
 
Q6
K10864
K1074
104
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 3 Jack Lowe - Terry Potter 620   100 0 4= by S Lead A
6 Alan Frost - Joanne Evans 4 Alan Whittam - Paul Evans 200   50 50 5-2 by W Lead 5
5 Colin Beesley - Kep Simcox 1 Dytria - Sturwies   100 0 100 4-1 by S Lead A

Board

8

 Q874
94
J93
Q432
5
4 18
13
Bill Wattleworth
Peter Richmond
 
K109532

6542
J87
AKJ1087652
AK
K10
par:-450.4+1 (E)
 NT
N  6  6  2  5  2
S  6  6  1  5  2
E  6  611  710
W  6  611  710
Double Dummy Solv:Bo Haglund
 
AJ6
Q3
Q1087
A965
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Alan Frost - Joanne Evans 4 Alan Whittam - Paul Evans   980 50 50 6= by E Lead A
5 Colin Beesley - Kep Simcox 1 Dytria - Sturwies   980 50 50 6= by E Lead A
2 Bill Wattleworth - Peter Richmond 3 Jack Lowe - Terry Potter     50 50 ??

Board

9

 A7
J963
AQJ952
4
12
7 11
10
Bill Wattleworth
Peter Richmond
 
QJ842
7
108743
A8		 K653
Q1042
K6
K106
par:140.3 (N)
 NT
N  9  7  9  5  6
S  9  7  9  5  6
E  4  6  3  8  7
W  3  4  3  8  6
Double Dummy Solv:Bo Haglund
 
109
AK85

QJ97532
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Colin Beesley - Kep Simcox 6 Alan Frost - Joanne Evans   50 75 25 4-1 by S Lead Q
3 Jack Lowe - Terry Potter 4 Alan Whittam - Paul Evans   50 75 25 4-1 by S Lead Q
2 Bill Wattleworth - Peter Richmond 1 Dytria - Sturwies   140 0 100 3= by W Lead 4

Board

10

 74
Q108642
KQ1096
7
15 11
7
Bill Wattleworth
Peter Richmond
 
AJ108
AK953
J7
Q5		 65
7
A8543
AK1096
par:-600.3NT (E)
 NT
N  3  5  6  4  3
S  4  5  6  4  4
E  9  8  7  8  9
W  9  8  7  9  9
Double Dummy Solv:Bo Haglund
 
KQ932
J
2
J87432
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Jack Lowe - Terry Potter 4 Alan Whittam - Paul Evans 100   100 0 3NT-1 by W Lead 6
5 Colin Beesley - Kep Simcox 6 Alan Frost - Joanne Evans   600 25 75 3NT= by W Lead 7
2 Bill Wattleworth - Peter Richmond 1 Dytria - Sturwies   600 25 75 3NT= by W Lead K

Board

11

 Q5
Q52
AQ742
843
10
4 9
17
Bill Wattleworth
Peter Richmond
 
973
K964
J965
107		 J1064
10
3
AKJ9652
par:450.4+1 (N)
 NT
N  51111  8  6
S  51111  8  6
E  8  2  2  4  4
W  8  2  2  4  4
Double Dummy Solv:Bo Haglund
 
AK82
AJ873
K108
Q
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 1 Dytria - Sturwies 450   100 0 4+1 by S Lead 5
3 Jack Lowe - Terry Potter 4 Alan Whittam - Paul Evans 420   25 75 4= by S Lead T
5 Colin Beesley - Kep Simcox 6 Alan Frost - Joanne Evans 420   25 75 4= by S Lead T

Board

12

 Q952
QJ872
1054
J
6
10 22
2
Bill Wattleworth
Peter Richmond
 
74
653
K96
AK1082		 AK
AK4
AQ2
Q7543
par:-990.6NT (E)
 NT
N  1  2  3  5  1
S  1  2  3  5  1
E1211  9  812
W1211  9  812
Double Dummy Solv:Bo Haglund
 
J10863
109
J873
96
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Colin Beesley - Kep Simcox 6 Alan Frost - Joanne Evans   490 100 0 3NT+3 by E Lead 6
3 Jack Lowe - Terry Potter 4 Alan Whittam - Paul Evans   920 50 50 6= by W Lead Q
2 Bill Wattleworth - Peter Richmond 1 Dytria - Sturwies   940 0 100 6+1 by E Lead J

Board

13

 K54
KJ10
1085
QJ75
10
0 22
8
Bill Wattleworth
Peter Richmond
 
876
97542
63
963		 AQ9
A863
KQ7
AK4
par:-110.2 (E)
 NT
N  6  8  5  6  6
S  6  7  5  6  6
E  7  5  8  7  7
W  7  5  8  7  7
Double Dummy Solv:Bo Haglund
 
J1032
Q
AJ942
1082
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 4 Alan Whittam - Paul Evans 200   100 0 4-2 by E Lead J
3 Jack Lowe - Terry Potter 5 Colin Beesley - Kep Simcox 100   25 75 2NT-1 by E Lead 4
1 Dytria - Sturwies 6 Alan Frost - Joanne Evans 100   25 75 3-1 by E Lead J

Board

14

 84
103
AKJ2
Q9732
10
6 9
15
Bill Wattleworth
Peter Richmond
 
QJ2
K98765
854
10		 K10975
QJ4
107
K65
par:920.6 (N)
 NT
N1112  5  611
S1112  5  611
E  2  1  7  7  2
W  2  1  7  7  2
Double Dummy Solv:Bo Haglund
 
A63
A2
Q963
AJ84
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dytria - Sturwies 6 Alan Frost - Joanne Evans 460   100 0 3NT+2 by S Lead 5
3 Jack Lowe - Terry Potter 5 Colin Beesley - Kep Simcox 420   50 50 5+1 by S Lead T
2 Bill Wattleworth - Peter Richmond 4 Alan Whittam - Paul Evans 50   0 100 3-1 by E Lead A

Board

15

 973
8
A987432
K3
7
8 11
14
Bill Wattleworth
Peter Richmond
 
J864
AJ93
J10
J96		 KQ102
Q76
Q5
Q1087
par:630.3NT+1 (N)
 NT
N  610  7  610
S  610  8  610
E  6  2  5  6  3
W  6  2  5  6  3
Double Dummy Solv:Bo Haglund
 
A5
K10542
K6
A542
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dytria - Sturwies 6 Alan Frost - Joanne Evans 210   100 0 1NT+4 by N Lead K
3 Jack Lowe - Terry Potter 5 Colin Beesley - Kep Simcox 130   25 75 2+2 by N Lead 7
2 Bill Wattleworth - Peter Richmond 4 Alan Whittam - Paul Evans 130   25 75 4= by N Lead K

Board

16

 KQ92
A86
Q
A5432
15
8 12
5
Bill Wattleworth
Peter Richmond
 
A653
7432
J9
K86		 74
KJ10
AK876
J97
par:110.1+1 (N)
 NT
N  8  6  7  8  7
S  8  6  7  8  7
E  5  7  6  5  6
W  4  7  6  5  6
Double Dummy Solv:Bo Haglund
 
J108
Q95
105432
Q10
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bill Wattleworth - Peter Richmond 4 Alan Whittam - Paul Evans 100   100 0 2-1 by W Lead K
3 Jack Lowe - Terry Potter 5 Colin Beesley - Kep Simcox   50 25 75 3-1 by N Lead 7
1 Dytria - Sturwies 6 Alan Frost - Joanne Evans   50 25 75 1-1 by N Lead A

Board

17

 42
10873
K964
J52
4
8 9
19
dytria
sturwies
 
AJ9863

J82
Q973		 Q1075
AQJ962
753
par:-100.5X-1 (S)
 NT
N  9  6  5  1  6
S10  6  5  1  6
E  3  4  810  7
W  3  4  810  7
Double Dummy Solv:Bo Haglund
 
K
K54
AQ10
AK10864
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dytria - Sturwies 3 Jack Lowe - Terry Potter   50 100 0 3-1 by S Lead J
4 Alan Whittam - Paul Evans 5 Colin Beesley - Kep Simcox   450 50 50 4+1 by W Lead 2
2 Bill Wattleworth - Peter Richmond 6 Alan Frost - Joanne Evans   480 0 100 4+2 by W Lead 2

Board

18

 A32
106
A102
J8632
9
10 8
13
dytria
sturwies
 
KJ98
432

AQ10754		 Q6
K975
QJ86543
par:120.1NT+1 (N)
 NT
N  7  8  5  7  8
S  7  8  6  7  8
E  6  5  5  5  5
W  6  5  5  5  5
Double Dummy Solv:Bo Haglund
 
10754
AQJ8
K97
K9
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Alan Whittam - Paul Evans 5 Colin Beesley - Kep Simcox 1100   100 0 4X-5 by E Lead 7
2 Bill Wattleworth - Peter Richmond 6 Alan Frost - Joanne Evans 150   50 50 2-3 by W Lead T
1 Dytria - Sturwies 3 Jack Lowe - Terry Potter   300 0 100 5-3 by N Lead Q

Board

19

 Q85
KJ1065
K94
98
9
9 8
14
dytria
sturwies
 
1076
Q8
872
AQJ105		 K943
A9743
J5
42
par:400.3NT (N)
 NT
N  7  9  7  7  9
S  7  9  7  7  9
E  6  4  5  6  4
W  6  4  5  6  4
Double Dummy Solv:Bo Haglund
 
AJ2
2
AQ1063
K763
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Alan Whittam - Paul Evans 5 Colin Beesley - Kep Simcox 150   75 25 2NT+1 by S Lead Q
1 Dytria - Sturwies 3 Jack Lowe - Terry Potter 150   75 25 2NT+1 by S Lead T
2 Bill Wattleworth - Peter Richmond 6 Alan Frost - Joanne Evans 90   0 100 2= by S Lead 7

Board

20

 A3
AQJ8
AJ6
AJ106
21
7 3
9
dytria
sturwies
 
Q10986
5
KQ75
752		 K42
7632
432
843
par:650.4+1 (N)
 NT
N11  911  710
S11  911  710
E  2  4  2  6  2
W  2  4  2  6  2
Double Dummy Solv:Bo Haglund
 
J75
K1094
1098
KQ9
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Dytria - Sturwies 3 Jack Lowe - Terry Potter 660   100 0 3NT+2 by N Lead 2
2 Bill Wattleworth - Peter Richmond 6 Alan Frost - Joanne Evans 650   50 50 4+1 by N Lead 4
4 Alan Whittam - Paul Evans 5 Colin Beesley - Kep Simcox 630   0 100 3NT+1 by N Lead 2

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  • Progressive Podium for game:2023-03-05 #18411 Lancashire Online LOP Open Pairs
    		•  
    BoardN Codice1 Player1 Codice2 Player2
    20 dytria   Dytria sturwies   Sturwies

    PodioProgressivo not implemented for mySql

  • Progressive Podium (with average) for game:2023-03-05 #18411 Lancashire Online LOP Open Pairs
    		•  
    BoardN Codice1 Player1 Codice2 Player2