Hands of game 2023-04-16 #98901 Lancashire Online LOP Open Pairs -

Board

1

 Q965
Q8543
8
Q73
6
15 14
5
Alan Frost
Joanne Evans
 
K108
A6
43
AKJ952		 AJ7
K2
KQJ962
106
par:-430.3NT+1 (E)
 NT
N  2  2  6  3  2
S  2  2  6  3  2
E1111  71010
W1111  71010
Double Dummy Solv:Bo Haglund
 
432
J1097
A1075
84
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Joan Cann - Joyce Truffas 8 Linda Smith - Michael Tomlinson 150   100 0 6NT-3 by E Lead J
9 Alan Frost - Joanne Evans 1 Jeff Smith - Marianne Farr 100   50 50 3NT-2 by W Lead 4
6 Monica Cartwright - Sue Woodcock 10 Barbara Heaton - Cath Ashworth 100   50 50 3NT-2 by W Lead 4
3 Bill Wattleworth - Peter Richmond 5 Jack Lowe - Terry Potter 100   50 50 3NT-2 by W Lead 4
7 Ann Wilkins - Elizabeth Fewster 4 Alan Whittam - Paul Evans 50   0 100 3NT-1 by W Lead 4

Board

2

 7
AQ107
A863
Q643
12
4 17
7
Jeff Smith
Marianne Farr
 
98543
653
K5
J109		 AKQJ102
K2
J7
K82
par:100.3X-1 (E)
 NT
N  7  9  9  5  5
S  7  8  8  4  4
E  6  4  4  8  7
W  6  4  4  8  7
Double Dummy Solv:Bo Haglund
 
6
J984
Q10942
A75
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Monica Cartwright - Sue Woodcock 10 Barbara Heaton - Cath Ashworth   100 100 0 5-1 by S Lead 9
2 Joan Cann - Joyce Truffas 8 Linda Smith - Michael Tomlinson   170 75 25 3+1 by E Lead 4
7 Ann Wilkins - Elizabeth Fewster 4 Alan Whittam - Paul Evans   420 25 75 4= by E Lead 4
3 Bill Wattleworth - Peter Richmond 5 Jack Lowe - Terry Potter   420 25 75 4= by E Lead 9
9 Alan Frost - Joanne Evans 1 Jeff Smith - Marianne Farr   420 25 75 4= by E Lead 9

Board

3

 Q832
A10
KJ9
J854
11
14 10
5
Joan Cann
Joyce Truffas
 
KJ
Q92
AQ842
Q93		 107
K876543
76
AK
par:-650.5 (W)
 NT
N  8  5  2  7  2
S  8  5  2  7  2
E  5  810  5  8
W  5  811  5  8
Double Dummy Solv:Bo Haglund
 
A9654
J
1053
10762
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
9 Alan Frost - Joanne Evans 10 Barbara Heaton - Cath Ashworth   620 100 0 4= by W Lead 2
2 Joan Cann - Joyce Truffas 1 Jeff Smith - Marianne Farr   650 37.5 62.5 4+1 by E Lead 6
8 Linda Smith - Michael Tomlinson 5 Jack Lowe - Terry Potter   650 37.5 62.5 5= by W Lead 2
6 Monica Cartwright - Sue Woodcock 7 Ann Wilkins - Elizabeth Fewster   650 37.5 62.5 4+1 by W Lead 4
3 Bill Wattleworth - Peter Richmond 4 Alan Whittam - Paul Evans   650 37.5 62.5 4+1 by W Lead 2

Board

4

 8763
82
AJ105
A109
9
13 13
5
Joan Cann
Joyce Truffas
 
AJ95
QJ6
Q842
K3		 KQ10
K973
K6
Q862
par:-600.3NT (E)
 NT
N  6  5  4  4  4
S  6  5  4  4  4
E  7  7  8  9  9
W  7  8  8  9  9
Double Dummy Solv:Bo Haglund
 
42
A1054
973
J754
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
9 Alan Frost - Joanne Evans 10 Barbara Heaton - Cath Ashworth 100   87.5 12.5 3NT-1 by W Lead 5
8 Linda Smith - Michael Tomlinson 5 Jack Lowe - Terry Potter 100   87.5 12.5 3NT-1 by W Lead T
6 Monica Cartwright - Sue Woodcock 7 Ann Wilkins - Elizabeth Fewster   600 25 75 3NT= by W Lead 8
2 Joan Cann - Joyce Truffas 1 Jeff Smith - Marianne Farr   600 25 75 3NT= by W Lead 5
3 Bill Wattleworth - Peter Richmond 4 Alan Whittam - Paul Evans   600 25 75 3NT= by W Lead J

Board

5

 Q109643
A10
65
K109
9
13 9
9
Joan Cann
Joyce Truffas
 
AK82
654
K107
QJ8		 75
K73
AQ942
765
par:-120.2NT (E)
 NT
N  7  4  7  8  5
S  7  4  7  8  5
E  6  9  6  5  8
W  6  9  6  5  8
Double Dummy Solv:Bo Haglund
 
J
QJ982
J83
A432
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Jeff Smith - Marianne Farr 10 Barbara Heaton - Cath Ashworth 50   87.5 12.5 3NT-1 by W Lead 6
3 Bill Wattleworth - Peter Richmond 6 Monica Cartwright - Sue Woodcock 50   87.5 12.5 3-1 by E Lead J
2 Joan Cann - Joyce Truffas 5 Jack Lowe - Terry Potter   100 25 75 2-1 by N Lead 7
9 Alan Frost - Joanne Evans 7 Ann Wilkins - Elizabeth Fewster   100 25 75 2-1 by N Lead 7
8 Linda Smith - Michael Tomlinson 4 Alan Whittam - Paul Evans   100 25 75 2-1 by S Lead Q

Board

6

 QJ4
53
82
AQ9876
9
7 8
16
Joan Cann
Joyce Truffas
 
K985
62
K109543
J		 106
KJ10974
A7
1042
par:430.3NT+1 (N)
 NT
N10  6  6  810
S10  6  6  810
E  3  6  7  4  3
W  3  6  7  4  3
Double Dummy Solv:Bo Haglund
 
A732
AQ8
QJ6
K53
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Joan Cann - Joyce Truffas 5 Jack Lowe - Terry Potter 430   50 50 3NT+1 by S Lead 6
9 Alan Frost - Joanne Evans 7 Ann Wilkins - Elizabeth Fewster 430   50 50 3NT+1 by S Lead 5
8 Linda Smith - Michael Tomlinson 4 Alan Whittam - Paul Evans 430   50 50 3NT+1 by S Lead 6
1 Jeff Smith - Marianne Farr 10 Barbara Heaton - Cath Ashworth 430   50 50 3NT+1 by S Lead T
3 Bill Wattleworth - Peter Richmond 6 Monica Cartwright - Sue Woodcock 430   50 50 3NT+1 by S Lead 6

Board

7

 A87542
74
94
Q52
6
14 7
13
Joan Cann
Joyce Truffas
 
3
AKQ92
AJ3
10743		 K6
J103
K1087652
9
par:-500.5X-2 (N)
 NT
N  8  1  1  9  1
S  8  1  1  9  1
E  51111  4  7
W  51111  4  7
Double Dummy Solv:Bo Haglund
 
QJ109
865
Q
AKJ86
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
8 Linda Smith - Michael Tomlinson 6 Monica Cartwright - Sue Woodcock 140   87.5 12.5 3= by N Lead J
2 Joan Cann - Joyce Truffas 10 Barbara Heaton - Cath Ashworth 140   87.5 12.5 3= by N Lead J
1 Jeff Smith - Marianne Farr 7 Ann Wilkins - Elizabeth Fewster   100 37.5 62.5 4-1 by N Lead J
5 Jack Lowe - Terry Potter 4 Alan Whittam - Paul Evans   100 37.5 62.5 4-1 by N Lead J
9 Alan Frost - Joanne Evans 3 Bill Wattleworth - Peter Richmond   680 0 100 4+2 by W Lead 2

Board

8

 KQ6
A1097
J94
932
10
11 15
4
Joan Cann
Joyce Truffas
 
A9743
6
K83
A865		 J5
Q2
AQ105
KQJ107
par:-400.5 (E)
 NT
N  2  2  8  3  3
S  2  2  8  3  3
E1110  5  9  7
W1110  5  9  7
Double Dummy Solv:Bo Haglund
 
1082
KJ8543
762
4
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
8 Linda Smith - Michael Tomlinson 6 Monica Cartwright - Sue Woodcock   400 50 50 5= by E Lead 4
9 Alan Frost - Joanne Evans 3 Bill Wattleworth - Peter Richmond   400 50 50 5= by E Lead 3
2 Joan Cann - Joyce Truffas 10 Barbara Heaton - Cath Ashworth   400 50 50 5= by E Lead 5
5 Jack Lowe - Terry Potter 4 Alan Whittam - Paul Evans   400 50 50 5= by E Lead 5
1 Jeff Smith - Marianne Farr 7 Ann Wilkins - Elizabeth Fewster   400 50 50 5= by E Lead 5

Board

9

 KQ865
987
J3
J107
7
9 16
8
Joan Cann
Joyce Truffas
 
J1073
KJ3
1092
A95		 A94
5
AKQ876
K83
par:-630.3NT+1 (E)
 NT
N  4  2  6  4  2
S  4  2  6  4  2
E  811  7  910
W  811  7  910
Double Dummy Solv:Bo Haglund
 
2
AQ10642
54
Q642
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
10 Barbara Heaton - Cath Ashworth 7 Ann Wilkins - Elizabeth Fewster   630 87.5 12.5 3NT+1 by W Lead 8
8 Linda Smith - Michael Tomlinson 9 Alan Frost - Joanne Evans   630 87.5 12.5 3NT+1 by W Lead 9
5 Jack Lowe - Terry Potter 6 Monica Cartwright - Sue Woodcock   660 50 50 3NT+2 by W Lead 9
2 Joan Cann - Joyce Truffas 4 Alan Whittam - Paul Evans   690 25 75 3NT+3 by W Lead 6
1 Jeff Smith - Marianne Farr 3 Bill Wattleworth - Peter Richmond   800 0 100 4X-4 by S Lead T

Board

10

 Q843
109

AJ97643
7
5 11
17
Joan Cann
Joyce Truffas
 
J106
742
J632
K102		 K975
A5
Q985
Q85
par:620.4 (N)
 NT
N  9  810  8  9
S  9  710  8  8
E  4  4  1  4  4
W  4  4  1  4  4
Double Dummy Solv:Bo Haglund
 
A2
KQJ863
AK1074
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Joan Cann - Joyce Truffas 4 Alan Whittam - Paul Evans 680   75 25 4+2 by S Lead J
5 Jack Lowe - Terry Potter 6 Monica Cartwright - Sue Woodcock 680   75 25 5+1 by S Lead J
1 Jeff Smith - Marianne Farr 3 Bill Wattleworth - Peter Richmond 680   75 25 4+2 by S Lead J
8 Linda Smith - Michael Tomlinson 9 Alan Frost - Joanne Evans 650   25 75 4+1 by S Lead 2
10 Barbara Heaton - Cath Ashworth 7 Ann Wilkins - Elizabeth Fewster 620   0 100 4= by S Lead 4

Board

11

 87432
4
AK94
J97
8
11 8
13
Joan Cann
Joyce Truffas
 
KJ
J10972
Q1062
A4		 A105
Q53
873
Q1083
par:100.2NTX-1 (E)
 NT
N  7  6  6  8  6
S  7  6  6  8  6
E  6  7  7  5  7
W  6  7  7  5  7
Double Dummy Solv:Bo Haglund
 
Q96
AK86
J5
K652
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Jeff Smith - Marianne Farr 8 Linda Smith - Michael Tomlinson 140   100 0 3= by N Lead 3
4 Alan Whittam - Paul Evans 6 Monica Cartwright - Sue Woodcock 110   50 50 2= by S Lead J
5 Jack Lowe - Terry Potter 9 Alan Frost - Joanne Evans 110   50 50 2= by S Lead J
2 Joan Cann - Joyce Truffas 7 Ann Wilkins - Elizabeth Fewster 110   50 50 2= by S Lead J
10 Barbara Heaton - Cath Ashworth 3 Bill Wattleworth - Peter Richmond   50 0 100 2-1 by S Lead J

Board

12

 8
A1053
102
QJ10854
7
11 14
8
Joan Cann
Joyce Truffas
 
A1076
K4
J53
K973		 KQJ953
QJ76
KQ9
par:-450.4+1 (E)
 NT
N  8  6  4  2  3
S  8  5  4  2  3
E  5  7  611  7
W  5  7  611  7
Double Dummy Solv:Bo Haglund
 
42
982
A8764
A62
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
10 Barbara Heaton - Cath Ashworth 3 Bill Wattleworth - Peter Richmond   450 50 50 4+1 by E Lead A
4 Alan Whittam - Paul Evans 6 Monica Cartwright - Sue Woodcock   450 50 50 4+1 by W Lead Q
1 Jeff Smith - Marianne Farr 8 Linda Smith - Michael Tomlinson   450 50 50 4+1 by E Lead 2
2 Joan Cann - Joyce Truffas 7 Ann Wilkins - Elizabeth Fewster   450 50 50 4+1 by E Lead 8
5 Jack Lowe - Terry Potter 9 Alan Frost - Joanne Evans   450 50 50 4+1 by E Lead 4

Board

13

 98
975
AQ432
A98
10
10 9
11
Alan Whittam
Paul Evans
 
Q103
AQ4
106
Q10632		 AK76
1063
J75
J75
par:110.2+1 (N)
 NT
N  5  9  8  5  7
S  5  9  8  6  7
E  8  4  5  7  5
W  8  4  5  7  5
Double Dummy Solv:Bo Haglund
 
J542
KJ82
K98
K4
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
5 Jack Lowe - Terry Potter 1 Jeff Smith - Marianne Farr     50 50 PASS
2 Joan Cann - Joyce Truffas 6 Monica Cartwright - Sue Woodcock     50 50 PASS
7 Ann Wilkins - Elizabeth Fewster 3 Bill Wattleworth - Peter Richmond     50 50 PASS
10 Barbara Heaton - Cath Ashworth 8 Linda Smith - Michael Tomlinson     50 50 PASS
4 Alan Whittam - Paul Evans 9 Alan Frost - Joanne Evans     50 50 PASS

Board

14

 Q854
J107
J1032
76
4
10 15
11
Joan Cann
Joyce Truffas
 
K632
KQ6
Q6
10532		 J107
A942
K875
AK
par:-420.4 (E)
 NT
N  5  4  3  3  4
S  5  4  4  3  5
E  8  9  910  8
W  8  9  910  8
Double Dummy Solv:Bo Haglund
 
A9
853
A94
QJ984
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Joan Cann - Joyce Truffas 6 Monica Cartwright - Sue Woodcock 100   87.5 12.5 3NT-2 by E Lead 8
7 Ann Wilkins - Elizabeth Fewster 3 Bill Wattleworth - Peter Richmond 100   87.5 12.5 3NT-2 by E Lead 8
10 Barbara Heaton - Cath Ashworth 8 Linda Smith - Michael Tomlinson   400 37.5 62.5 3NT= by E Lead Q
4 Alan Whittam - Paul Evans 9 Alan Frost - Joanne Evans   400 37.5 62.5 3NT= by E Lead Q
5 Jack Lowe - Terry Potter 1 Jeff Smith - Marianne Farr   430 0 100 3NT+1 by E Lead Q

Board

15

 K10
QJ1052
652
K74
9
13 6
12
Joan Cann
Joyce Truffas
 
QJ65
A
J94
AJ985		 97432
97
A108
Q32
par:300.4X-2 (E)
 NT
N  4  810  4  7
S  4  810  4  7
E  8  4  3  8  6
W  8  4  3  8  6
Double Dummy Solv:Bo Haglund
 
A8
K8643
KQ73
106
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Monica Cartwright - Sue Woodcock 9 Alan Frost - Joanne Evans 620   87.5 12.5 4= by S Lead 9
10 Barbara Heaton - Cath Ashworth 5 Jack Lowe - Terry Potter 620   87.5 12.5 4= by S Lead Q
2 Joan Cann - Joyce Truffas 3 Bill Wattleworth - Peter Richmond 100   50 50 4-2 by E Lead 4
7 Ann Wilkins - Elizabeth Fewster 8 Linda Smith - Michael Tomlinson 50   25 75 4-1 by E Lead 4
4 Alan Whittam - Paul Evans 1 Jeff Smith - Marianne Farr   140 0 100 2+1 by E Lead A

Board

16

 K83
A
AQ6
1097542
13
12 7
8
Alan Whittam
Paul Evans
 
Q965
63
KJ5
KQJ8		 A104
K842
10873
63
par:-100.3X-1 (N)
 NT
N  7  7  8  7  5
S  7  7  8  7  5
E  6  6  4  5  8
W  6  6  4  5  8
Double Dummy Solv:Bo Haglund
 
J72
QJ10975
942
A
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Monica Cartwright - Sue Woodcock 9 Alan Frost - Joanne Evans 140   100 0 2+1 by N Lead A
2 Joan Cann - Joyce Truffas 3 Bill Wattleworth - Peter Richmond 100   75 25 2-1 by W Lead A
7 Ann Wilkins - Elizabeth Fewster 8 Linda Smith - Michael Tomlinson   90 50 50 1NT= by W Lead 9
4 Alan Whittam - Paul Evans 1 Jeff Smith - Marianne Farr   100 25 75 4-2 by S Lead K
10 Barbara Heaton - Cath Ashworth 5 Jack Lowe - Terry Potter   150 0 100 3-3 by N Lead 2

Board

17

 AKJ102

J1098532
5
9
16 7
8
Jeff Smith
Marianne Farr
 
Q
AJ1086

AKQ10987		 653
K9543
K76
J2
par:-100.6X-1 (N)
 NT
N  112  011  1
S  112  011  1
E11  112  0  1
W12  112  0  1
Double Dummy Solv:Bo Haglund
 
9874
Q72
AQ4
643
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Bill Wattleworth - Peter Richmond 8 Linda Smith - Michael Tomlinson 1310   100 0 6X+1 by N Lead 4
6 Monica Cartwright - Sue Woodcock 1 Jeff Smith - Marianne Farr   300 75 25 6X-2 by N Lead J
7 Ann Wilkins - Elizabeth Fewster 5 Jack Lowe - Terry Potter   420 50 50 5+1 by W Lead A
2 Joan Cann - Joyce Truffas 9 Alan Frost - Joanne Evans   920 25 75 6= by W Lead A
4 Alan Whittam - Paul Evans 10 Barbara Heaton - Cath Ashworth   1310 0 100 6X+1 by E Lead A

Board

18

 94
AK
109754
AQ64
13
11 9
7
Jeff Smith
Marianne Farr
 
QJ53
103
AKJ6
1093		 A1076
Q754
Q
J852
par:100.2X-1 (E)
 NT
N  7  8  8  5  6
S  7  8  8  5  6
E  6  5  5  7  6
W  6  5  5  7  6
Double Dummy Solv:Bo Haglund
 
K82
J9862
832
K7
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Alan Whittam - Paul Evans 10 Barbara Heaton - Cath Ashworth 50   87.5 12.5 2-1 by E Lead 3
6 Monica Cartwright - Sue Woodcock 1 Jeff Smith - Marianne Farr 50   87.5 12.5 2-1 by W Lead K
2 Joan Cann - Joyce Truffas 9 Alan Frost - Joanne Evans   90 50 50 1NT= by W Lead 4
3 Bill Wattleworth - Peter Richmond 8 Linda Smith - Michael Tomlinson   100 12.5 87.5 2-1 by N Lead Q
7 Ann Wilkins - Elizabeth Fewster 5 Jack Lowe - Terry Potter   100 12.5 87.5 3-1 by S Lead A

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    BoardN Codice1 Player1 Codice2 Player2
    18 jeffsmith   Jeff Smith MVFarr   Marianne Farr

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  • Progressive Podium (with average) for game:2023-04-16 #98901 Lancashire Online LOP Open Pairs
    		•  
    BoardN Codice1 Player1 Codice2 Player2