Hands of game 2021-09-13 #20224 Purley Bridge Club Duplicate -

Board

1

KQJ853
J
KQ
8765
12
12 11
5
Beryl Blizard
Elaine Cann
 
A
KQ9863
732
K94
10942
A104
AJ9
Q103
par:-450.4+1 (E)
 NT
N  6  4  2  7  3
S  6  4  2  7  3
E  7  911  6  8
W  7  911  6  8
Double Dummy Solv:Bo Haglund
 
76
752
108654
AJ2
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bob Mcmahon - Nigel Marks 4 Brenda Goodwin - Dick Goodwin   170 83.33 16.67 3+1 by W Lead K
7 Alan Walker - Sharon Walker 6 Mary Dibbs - Paul Dibbs   170 83.33 16.67 3+1 by W Lead K
8 Beryl Blizard - Elaine Cann 1 Brigitte Montali - Mary Hyde   500 16.67 83.33 4X-3 by N Lead A
5 Steve Goldman - Terry Mitchell 3 Carol Letts - David Rothberg   500 16.67 83.33 4X-3 by N Lead A

Board

2

K8
Q7642
AK53
K9
15
6 9
10
Beryl Blizard
Elaine Cann
 
7543
103
J109
AJ42
AJ1092
KJ
76
10765
par:300.4X-2 (E)
 NT
N  51010  5  7
S  51010  5  7
E  8  3  3  8  4
W  8  3  3  8  4
Double Dummy Solv:Bo Haglund
 
Q6
A985
Q842
Q83
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
8 Beryl Blizard - Elaine Cann 1 Brigitte Montali - Mary Hyde 620   100 0 4= by N Lead T
7 Alan Walker - Sharon Walker 6 Mary Dibbs - Paul Dibbs 170   50 50 3+1 by N Lead A
2 Bob Mcmahon - Nigel Marks 4 Brenda Goodwin - Dick Goodwin 170   50 50 3+1 by N Lead A
5 Steve Goldman - Terry Mitchell 3 Carol Letts - David Rothberg   100 0 100 5-1 by N Lead A

Board

3

93
Q7
J108763
K54
6
11 19
4
Beryl Blizard
Elaine Cann
 
7
KJ94
KQ4
Q8632
AK1082
A62
A95
A9
par:-660.3NT+2 (E)
 NT
N  2  4  2  3  2
S  2  4  2  3  2
E11  9111011
W11  9111011
Double Dummy Solv:Bo Haglund
 
QJ654
10853
2
J107
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bob Mcmahon - Nigel Marks 4 Brenda Goodwin - Dick Goodwin 300   100 0 6NT-3 by E Lead 2
8 Beryl Blizard - Elaine Cann 1 Brigitte Montali - Mary Hyde   660 33.33 66.67 3NT+2 by E Lead 5
5 Steve Goldman - Terry Mitchell 3 Carol Letts - David Rothberg   660 33.33 66.67 3NT+2 by E Lead 3
7 Alan Walker - Sharon Walker 6 Mary Dibbs - Paul Dibbs   660 33.33 66.67 3NT+2 by E Lead 2

Board

4

KJ972
K3
A96
A86
15
7 13
5
Bob McMahon
Nigel Marks
 
Q108
1098
K103
Q542
A64
A74
Q542
K107
par:-90.1NT (E)
 NT
N  6  6  7  6  6
S  6  6  7  6  6
E  7  6  5  6  7
W  7  7  6  7  7
Double Dummy Solv:Bo Haglund
 
53
QJ652
J87
J93
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bob Mcmahon - Nigel Marks 1 Brigitte Montali - Mary Hyde 150   100 0 1NT+2 by S Lead 2
4 Brenda Goodwin - Dick Goodwin 3 Carol Letts - David Rothberg 110   66.67 33.33 2= by N Lead 2
5 Steve Goldman - Terry Mitchell 7 Alan Walker - Sharon Walker 90   33.33 66.67 1NT= by S Lead 2
8 Beryl Blizard - Elaine Cann 6 Mary Dibbs - Paul Dibbs   300 0 100 2-3 by N Lead 2

Board

5

J72
J653
Q10
Q643
6
5 15
14
Bob McMahon
Nigel Marks
 
KQ3
74
8753
9875
964
KQ
AJ962
AJ10
par:-110.3 (E)
 NT
N  5  4  8  7  6
S  5  4  8  7  6
E  8  9  5  5  6
W  8  9  5  5  6
Double Dummy Solv:Bo Haglund
 
A1085
A10982
K4
K2
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
8 Beryl Blizard - Elaine Cann 6 Mary Dibbs - Paul Dibbs 110   100 0 2= by S Lead 3
4 Brenda Goodwin - Dick Goodwin 3 Carol Letts - David Rothberg 50   66.67 33.33 4-1 by E Lead A
2 Bob Mcmahon - Nigel Marks 1 Brigitte Montali - Mary Hyde   100 16.67 83.33 3-1 by S Lead 8
5 Steve Goldman - Terry Mitchell 7 Alan Walker - Sharon Walker   100 16.67 83.33 3-1 by N Lead A

Board

6

65
J873
843
QJ76
4
6 17
13
Bob McMahon
Nigel Marks
 
Q93
9642
A10
5432
J842
AK5
KQ975
A
par:-620.4 (E)
 NT
N  6  3  4  3  5
S  6  3  4  3  5
E  6  9  810  8
W  6  9  810  8
Double Dummy Solv:Bo Haglund
 
AK107
Q10
J62
K1098
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
8 Beryl Blizard - Elaine Cann 6 Mary Dibbs - Paul Dibbs   110 100 0 2= by W Lead 8
5 Steve Goldman - Terry Mitchell 7 Alan Walker - Sharon Walker   140 66.67 33.33 1+2 by E Lead Q
4 Brenda Goodwin - Dick Goodwin 3 Carol Letts - David Rothberg   170 33.33 66.67 1+3 by E Lead Q
2 Bob Mcmahon - Nigel Marks 1 Brigitte Montali - Mary Hyde   200 0 100 2+3 by E Lead A

Board

7

KQJ974
A3
9
QJ108
13
11 3
13
Bob McMahon
Nigel Marks
 
1063
KJ4
8642
AK2
85
Q875
J
976543
par:2140.7 (N)
 NT
N  613  81111
S  613  81111
E  7  0  4  0  0
W  7  0  4  0  0
Double Dummy Solv:Bo Haglund
 
A2
10962
AKQ10753
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Brenda Goodwin - Dick Goodwin 7 Alan Walker - Sharon Walker 640   100 0 5+2 by S Lead A
1 Brigitte Montali - Mary Hyde 6 Mary Dibbs - Paul Dibbs 630   66.67 33.33 3NT+1 by N Lead 5
8 Beryl Blizard - Elaine Cann 5 Steve Goldman - Terry Mitchell 620   33.33 66.67 4= by N Lead 9
2 Bob Mcmahon - Nigel Marks 3 Carol Letts - David Rothberg   100 0 100 5-1 by N Lead J

Board

8

J
J75
A8732
K1053
9
16 6
9
Bob McMahon
Nigel Marks
 
K74
AQ109
KQ95
Q6
AQ10652
62
64
984
par:-420.4 (E)
 NT
N  8  6  6  3  5
S  8  6  6  3  5
E  5  6  610  8
W  5  6  610  8
Double Dummy Solv:Bo Haglund
 
983
K843
J10
AJ72
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Brenda Goodwin - Dick Goodwin 7 Alan Walker - Sharon Walker 50   100 0 4-1 by E Lead 9
8 Beryl Blizard - Elaine Cann 5 Steve Goldman - Terry Mitchell   140 50 50 2+1 by E Lead J
2 Bob Mcmahon - Nigel Marks 3 Carol Letts - David Rothberg   140 50 50 3= by E Lead J
1 Brigitte Montali - Mary Hyde 6 Mary Dibbs - Paul Dibbs   170 0 100 3+1 by E Lead J

Board

9

KQ1082
85
K97
J76
9
5 17
9
Bob McMahon
Nigel Marks
 
7653
A7432
J52
9
AJ9
K96
A108
KQ52
par:-140.2+1 (E)
 NT
N  7  6  4  5  6
S  7  6  4  5  5
E  6  6  9  7  7
W  6  6  9  7  7
Double Dummy Solv:Bo Haglund
 
4
QJ10
Q643
A10843
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bob Mcmahon - Nigel Marks 3 Carol Letts - David Rothberg   120 66.67 33.33 2NT= by E Lead 4
1 Brigitte Montali - Mary Hyde 6 Mary Dibbs - Paul Dibbs   120 66.67 33.33 2NT= by E Lead 4
4 Brenda Goodwin - Dick Goodwin 7 Alan Walker - Sharon Walker   120 66.67 33.33 2NT= by E Lead 4
8 Beryl Blizard - Elaine Cann 5 Steve Goldman - Terry Mitchell   150 0 100 2NT+1 by E Lead 8

Board

10

AQJ107
A
QJ73
543
14
8 6
12
Bob McMahon
Nigel Marks
 
543
K852
42
KQ62
K86
QJ10964
109
109
par:650.4+1 (N)
 NT
N  911  611  8
S  911  611  8
E  4  1  7  2  2
W  4  1  7  2  2
Double Dummy Solv:Bo Haglund
 
92
73
AK865
AJ87
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
4 Brenda Goodwin - Dick Goodwin 8 Beryl Blizard - Elaine Cann 600   100 0 5= by S Lead K
1 Brigitte Montali - Mary Hyde 5 Steve Goldman - Terry Mitchell 200   50 50 2+3 by N Lead Q
2 Bob Mcmahon - Nigel Marks 6 Mary Dibbs - Paul Dibbs 200   50 50 3+2 by N Lead Q
3 Carol Letts - David Rothberg 7 Alan Walker - Sharon Walker 100   0 100 3-1 by E Lead A

Board

11

AQ10642
6432
10
86
6
22 7
5
Bob McMahon
Nigel Marks
 
J8
AKQ8
AQ6
AQ109
93
J7
K8742
K742
par:-450.4+1 (E)
 NT
N  0  1  2  7  2
S  0  1  2  7  2
E111011  6  7
W111011  6  7
Double Dummy Solv:Bo Haglund
 
K75
1095
J953
J53
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Brigitte Montali - Mary Hyde 5 Steve Goldman - Terry Mitchell 100   83.33 16.67 3NT-2 by W Lead A
2 Bob Mcmahon - Nigel Marks 6 Mary Dibbs - Paul Dibbs 100   83.33 16.67 3NT-2 by W Lead 6
3 Carol Letts - David Rothberg 7 Alan Walker - Sharon Walker 50   33.33 66.67 5-1 by E Lead 5
4 Brenda Goodwin - Dick Goodwin 8 Beryl Blizard - Elaine Cann   460 0 100 3NT+2 by W Lead 2

Board

12

K6
J8
J10873
A853
9
9 10
12
Bob McMahon
Nigel Marks
 
AQ5
1096
9654
K92
J10974
A4
Q
QJ1064
par:300.4X-2 (E)
 NT
N  51010  4  7
S  51010  4  7
E  8  3  2  8  2
W  8  3  2  8  2
Double Dummy Solv:Bo Haglund
 
832
KQ7532
AK2
7
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Carol Letts - David Rothberg 7 Alan Walker - Sharon Walker 130   100 0 3+1 by N Lead A
4 Brenda Goodwin - Dick Goodwin 8 Beryl Blizard - Elaine Cann   140 33.33 66.67 3= by E Lead A
1 Brigitte Montali - Mary Hyde 5 Steve Goldman - Terry Mitchell   140 33.33 66.67 3= by E Lead A
2 Bob Mcmahon - Nigel Marks 6 Mary Dibbs - Paul Dibbs   140 33.33 66.67 3= by E Lead A

Board

13

K987542
J74

AJ4
9
11 7
13
Bob McMahon
Nigel Marks
 
A
1083
AQJ53
10872
J3
K52
K109874
53
par:1400.6NTX-5 (E)
 NT
N  9  51112  6
S  9  51112  6
E  1  8  2  1  7
W  1  8  2  1  7
Double Dummy Solv:Bo Haglund
 
Q106
AQ96
62
KQ96
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Brigitte Montali - Mary Hyde 4 Brenda Goodwin - Dick Goodwin 680   100 0 4+2 by N Lead T
2 Bob Mcmahon - Nigel Marks 7 Alan Walker - Sharon Walker 500   66.67 33.33 5X-2 by E Lead 6
3 Carol Letts - David Rothberg 8 Beryl Blizard - Elaine Cann 230   33.33 66.67 3+3 by N Lead 9
6 Mary Dibbs - Paul Dibbs 5 Steve Goldman - Terry Mitchell 100   0 100 4-1 by E Lead Q

Board

14

AJ94
1052
QJ5
K87
11
4 9
16
Bob McMahon
Nigel Marks
 
8632
A83
1096
932
Q107
KJ76
K8432
10
par:430.3NT+1 (N)
 NT
N11  7  8  910
S11  7  8  910
E  2  6  4  3  2
W  2  6  4  3  2
Double Dummy Solv:Bo Haglund
 
K5
Q94
A7
AQJ654
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Carol Letts - David Rothberg 8 Beryl Blizard - Elaine Cann 490   100 0 3NT+3 by N Lead 3
6 Mary Dibbs - Paul Dibbs 5 Steve Goldman - Terry Mitchell 460   66.67 33.33 3NT+2 by N Lead 6
2 Bob Mcmahon - Nigel Marks 7 Alan Walker - Sharon Walker 400   33.33 66.67 3NT= by S Lead 8
1 Brigitte Montali - Mary Hyde 4 Brenda Goodwin - Dick Goodwin   100 0 100 5-2 by S Lead 2

Board

15

A
K42
AK875
J1098
15
12 5
8
Bob McMahon
Nigel Marks
 
KJ4
Q963
J63
KQ3
1075
J1085
109
A542
par:140.2+1 (N)
 NT
N  810  6  9  8
S  810  6  9  8
E  5  3  7  4  5
W  5  3  7  4  5
Double Dummy Solv:Bo Haglund
 
Q98632
A7
Q42
76
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
1 Brigitte Montali - Mary Hyde 4 Brenda Goodwin - Dick Goodwin 500   100 0 1NTX-3 by W Lead 7
6 Mary Dibbs - Paul Dibbs 5 Steve Goldman - Terry Mitchell 140   33.33 66.67 2+1 by S Lead K
2 Bob Mcmahon - Nigel Marks 7 Alan Walker - Sharon Walker 140   33.33 66.67 2+1 by S Lead K
3 Carol Letts - David Rothberg 8 Beryl Blizard - Elaine Cann 140   33.33 66.67 3= by S Lead K

Board

16

10982
43
KJ83
854
4
15 6
15
Bob McMahon
Nigel Marks
 
J64
KQ2
A764
AJ2
753
A109865
Q10
97
par:-140.3 (E)
 NT
N  7  6  4  7  4
S  7  6  4  7  4
E  6  6  9  6  8
W  6  6  9  6  8
Double Dummy Solv:Bo Haglund
 
AKQ
J7
952
KQ1063
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
7 Alan Walker - Sharon Walker 8 Beryl Blizard - Elaine Cann   120 100 0 1NT+1 by W Lead 2
6 Mary Dibbs - Paul Dibbs 4 Brenda Goodwin - Dick Goodwin   140 50 50 3= by E Lead A
2 Bob Mcmahon - Nigel Marks 5 Steve Goldman - Terry Mitchell   140 50 50 2+1 by E Lead A
3 Carol Letts - David Rothberg 1 Brigitte Montali - Mary Hyde   150 0 100 4-3 by S Lead K

Board

17

AK109
J742
AJ8
J4
14
9 8
9
Bob McMahon
Nigel Marks
 
J7543
Q10
K97
K97

A853
Q105432
Q85
par:300.5X-2 (E)
 NT
N  8  4  810  7
S  8  4  810  7
E  4  9  5  3  5
W  4  9  5  3  5
Double Dummy Solv:Bo Haglund
 
Q862
K96
6
A10632
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Mary Dibbs - Paul Dibbs 4 Brenda Goodwin - Dick Goodwin 110   100 0 3= by S Lead 7
3 Carol Letts - David Rothberg 1 Brigitte Montali - Mary Hyde   50 50 50 1NT-1 by N Lead 5
7 Alan Walker - Sharon Walker 8 Beryl Blizard - Elaine Cann   50 50 50 1NT-1 by N Lead 4
2 Bob Mcmahon - Nigel Marks 5 Steve Goldman - Terry Mitchell   130 0 100 2+2 by E Lead 2

Board

18

KQ75
K5
KJ104
AQ3
18
4 15
3
Bob McMahon
Nigel Marks
 
J96
Q98
83
J10874
A82
AJ74
AQ765
5
par:-110.2 (E)
 NT
N  5  5  5  7  6
S  5  5  4  5  6
E  8  7  8  6  7
W  8  7  8  6  7
Double Dummy Solv:Bo Haglund
 
1043
10632
92
K962
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
3 Carol Letts - David Rothberg 1 Brigitte Montali - Mary Hyde   100 100 0 2NT-1 by N Lead 7
7 Alan Walker - Sharon Walker 8 Beryl Blizard - Elaine Cann   140 66.67 33.33 2+1 by E Lead 9
6 Mary Dibbs - Paul Dibbs 4 Brenda Goodwin - Dick Goodwin   200 16.67 83.33 2-2 by N Lead 5
2 Bob Mcmahon - Nigel Marks 5 Steve Goldman - Terry Mitchell   200 16.67 83.33 2-2 by S Lead 8

Board

19

Q93
AK8
2
J98764
10
5 13
12
Bob McMahon
Nigel Marks
 
1072
109542
K86
Q10
AKJ4
76
Q975
K52
par:90.2 (N)
 NT
N  8  6  7  6  6
S  8  6  7  5  6
E  5  7  6  6  7
W  5  7  6  6  7
Double Dummy Solv:Bo Haglund
 
865
QJ3
AJ1043
A3
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bob Mcmahon - Nigel Marks 8 Beryl Blizard - Elaine Cann 110   100 0 3= by N Lead A
6 Mary Dibbs - Paul Dibbs 3 Carol Letts - David Rothberg   50 66.67 33.33 3-1 by N Lead A
7 Alan Walker - Sharon Walker 1 Brigitte Montali - Mary Hyde   100 16.67 83.33 2NT-2 by S Lead 4
5 Steve Goldman - Terry Mitchell 4 Brenda Goodwin - Dick Goodwin   100 16.67 83.33 1NT-2 by S Lead T

Board

20

A4
K109
109652
1075
7
8 15
10
Brigitte Montali
Mary Hyde
 
Q972
AQ42
73
864
KJ3
8653
AQJ4
A2
par:-110.2 (E)
 NT
N  8  7  5  5  6
S  8  7  5  5  6
E  5  6  8  8  6
W  5  6  8  8  6
Double Dummy Solv:Bo Haglund
 
10865
J7
K8
KQJ93
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
6 Mary Dibbs - Paul Dibbs 3 Carol Letts - David Rothberg 200   100 0 4-2 by E Lead K
2 Bob Mcmahon - Nigel Marks 8 Beryl Blizard - Elaine Cann 110   66.67 33.33 2+1 by S Lead 7
7 Alan Walker - Sharon Walker 1 Brigitte Montali - Mary Hyde 100   16.67 83.33 1NT-1 by E Lead K
5 Steve Goldman - Terry Mitchell 4 Brenda Goodwin - Dick Goodwin 100   16.67 83.33 1NT-1 by W Lead T

Board

21

107
53
AK10753
J82
8
10 10
12
Brigitte Montali
Mary Hyde
 
KQ2
876
J64
A1074
9843
K
Q982
KQ93
par:140.3 (N)
 NT
N  5  7  9  7  8
S  5  7  9  7  8
E  8  6  3  6  5
W  7  6  1  6  3
Double Dummy Solv:Bo Haglund
 
AJ65
AQJ10942

65
NS-Pair EW-Pair N_S E_W NS EW Contract BBO
2 Bob Mcmahon - Nigel Marks 8 Beryl Blizard - Elaine Cann 200   100 0 3+2 by S Lead A
5 Steve Goldman - Terry Mitchell 4 Brenda Goodwin - Dick Goodwin 170   50 50 3+1 by S Lead 4
6 Mary Dibbs - Paul Dibbs 3 Carol Letts - David Rothberg 170   50 50 3+1 by S Lead 8
7 Alan Walker - Sharon Walker 1 Brigitte Montali - Mary Hyde   100 0 100 4-1 by S Lead 8

PodioProgressivo not implemented for mySql

  • Progressive Podium for game:2021-09-13 #20224 Purley Bridge Club Duplicate
  •  
    BoardN Codice1 Player1 Codice2 Player2
    21 brigittemo   Brigitte Montali maryhyde   Mary Hyde

    PodioProgressivo not implemented for mySql

  • Progressive Podium (with average) for game:2021-09-13 #20224 Purley Bridge Club Duplicate
  •  
    BoardN Codice1 Player1 Codice2 Player2